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PhysicsElectrostatics
An electric dipole of dipole moment $p = 5 \times 10^{-6}$ C·m is placed in a uniform electric field $E = 4 \times 10^5$ N/C. The dipole is rotated from a position of stable equilibrium to a position making $60°$ with the field. The change in potential energy is:
Options
1
$2$ J
2
$0.5$ J
3
$1$ J
4
$1.5$ J
Correct Answer
$1$ J
Solution
1

Potential energy of dipole: $U = -pE\cos\theta$

Stable equilibrium: $\theta_i = 0°$

$$U_i = -pE\cos 0° = -pE = -(5\times10^{-6})(4\times10^5) = -2 \text{ J}$$
2

Final position: $\theta_f = 60°$

$$U_f = -pE\cos 60° = -pE \cdot \frac{1}{2} = -1 \text{ J}$$$$\Delta U = U_f - U_i = -1 - (-2) = \boxed{1 \text{ J}}$$
$\Delta U = pE(1-\cos 60°)/1 = pE/2 = 1$ J
$U = -pE\cos\theta$ | Stable equilibrium at $\theta = 0°$
Theory: Electrostatics
1. Electric Dipole

An electric dipole consists of two equal and opposite charges $+q$ and $-q$ separated by distance $2l$ (or $d$). Dipole moment: $\vec{p} = q\vec{d}$ (from $-q$ to $+q$). SI unit: C·m (or Debye: $1$ D $= 3.33\times10^{-30}$ C·m). Torque in uniform field: $\vec{\tau} = \vec{p}\times\vec{E}$, magnitude $\tau = pE\sin\theta$. Potential energy: $U = -\vec{p}\cdot\vec{E} = -pE\cos\theta$. Work done rotating from $\theta_1$ to $\theta_2$: $W = pE(\cos\theta_1 - \cos\theta_2)$.

2. Equilibrium of Dipole

Stable equilibrium: $\theta = 0°$ (aligned with field). $U = -pE$ (minimum). Small perturbation → restoring torque → returns to $\theta = 0°$. Unstable equilibrium: $\theta = 180°$ (anti-aligned). $U = +pE$ (maximum). Small perturbation → torque pushes further away. Neutral: no torque at $\theta = 0°$ and $180°$. Maximum torque at $\theta = 90°$: $\tau = pE$. In non-uniform field: net force on dipole (towards stronger field for aligned dipole).

3. Electric Field of a Dipole

At axial point (on dipole axis, end-on position, distance $r >> l$): $E_{axial} = \frac{2kp}{r^3}$ (along $\vec{p}$). At equatorial point (perpendicular bisector, broad-side): $E_{equatorial} = \frac{kp}{r^3}$ (opposite to $\vec{p}$). Both fall off as $1/r^3$ (faster than monopole $1/r^2$). Ratio: $E_{axial}/E_{equatorial} = 2$ (at same distance). These formulas apply when $r >> l$ (dipole approximation).

4. Gauss Law for Dipole

Net charge of dipole $= 0$. So electric flux through any closed surface completely enclosing the dipole $= 0$ (Gauss law). But the field of a dipole is non-zero; flux cancels because field lines leave through one face and return through another. A dipole inside a Gaussian surface contributes zero net flux. This is why the electric field of a magnetic dipole (bar magnet) also follows $1/r^3$ at large distances (analogous structure).

5. Capacitor with Dielectric

Dielectric in electric field: polar molecules align with field (permanent dipoles). Non-polar molecules: induced dipoles. Both reduce net field inside dielectric. Dielectric constant $K = E_0/E$ where $E_0$ = field without dielectric, $E$ = field with dielectric. Capacitance with dielectric: $C = K\epsilon_0 A/d = KC_0$. Energy stored: $U = Q^2/(2C) = Q^2/(2KC_0)$. Inserting dielectric with battery connected: $V$ constant, $C$ increases, $Q$ increases, $U$ increases. With battery disconnected: $Q$ constant, $C$ increases, $V$ decreases, $U$ decreases.

6. Electrostatic Potential Energy

For point charge system: $U = \sum_{i 0). Negative if opposite (attractive, PE < 0). The PE is shared between the pair, not associated with one charge. For bringing charge $q$ from infinity to point of potential $V$: $W = qV$. This work is stored as PE.

7. Van de Graaff Generator

Electrostatic generator producing very high voltages (millions of volts). Working: positive charges sprayed onto moving belt at bottom. Belt carries charges up inside hollow sphere. Charges transferred to outer surface of sphere (charges always reside on outer surface of conductor). Potential builds up: $V = kQ/R$ (limited by corona discharge in air). Uses: accelerate charged particles (nuclear physics). Medical: cancer treatment. Demonstrate high-voltage phenomena. Can create potential difference of several MV.

8. Applications of Electric Dipole

Polar molecules: permanent dipole moments. Water: $p = 1.85$ D (large polar molecule). HCl: $p = 1.08$ D. CO$_2$: $p = 0$ (linear, symmetric, dipoles cancel). Microwave cooking: water molecules rotate to align with oscillating microwave field ($2.45$ GHz resonance) → molecular friction → heat. Dielectrics: alignment of molecular dipoles reduces field. Electrophoresis: charged biomolecules (DNA, proteins) move in electric field based on charge and size. NMR (Nuclear Magnetic Resonance): nuclear magnetic dipoles in magnetic field (analogous to electric dipole in E field).

Frequently Asked Questions
1. Why is stable equilibrium at θ=0° and not θ=180°?
At $\theta = 0°$: dipole aligned with field. $U = -pE$ (minimum possible energy). If displaced slightly: torque $\tau = pE\sin\delta \approx pE\delta$ acts to return it to $\theta=0°$ (restoring). This is stable equilibrium. At $\theta = 180°$: dipole anti-aligned. $U = +pE$ (maximum energy). If displaced slightly: torque acts to push it AWAY from $\theta=180°$ (destabilizing). This is unstable equilibrium. Analogy: ball at bottom of valley (stable) vs ball at top of hill (unstable).
2. What work must be done to rotate dipole from 0° to 60°?
Work done $=$ change in PE $= \Delta U = U_f - U_i$. Here $\Delta U = 1$ J. This 1 J of work is done by external agent (against the torque due to electric field). The field's torque $\tau = pE\sin\theta$ opposes the rotation (tries to bring dipole back to $\theta=0°$). So external agent must do positive work. This work is stored as increased potential energy of the dipole in the field.
3. What is the torque on the dipole at 60°?
$\tau = pE\sin 60° = (5\times10^{-6})(4\times10^5)(\sqrt{3}/2) = 2 \times \sqrt{3}/2 = \sqrt{3} \approx 1.73$ N·m. This torque acts to decrease $\theta$ (rotate dipole back toward $\theta = 0°$). To maintain 60°, external agent must apply equal and opposite torque of $1.73$ N·m.
4. What is the difference between torque and potential energy formula for dipoles?
Torque: $\tau = pE\sin\theta$ (maximum at $\theta = 90°$, zero at $\theta = 0°$ and $180°$). Potential energy: $U = -pE\cos\theta$ (minimum at $\theta = 0°$, maximum at $\theta = 180°$). Connection: $\tau = -dU/d\theta$. At $\theta = 90°$: torque is maximum, but this is not an equilibrium position. Both formulas use the angle between $\vec{p}$ and $\vec{E}$.
5. What is the dipole moment of water and why is it important?
Water (H$_2$O) has a dipole moment of $1.85$ D (Debye). The molecule is bent (V-shaped, bond angle $104.5°$) and the two O–H bonds each have partial charges ($\delta^+$ on H, $\delta^-$ on O). These partial dipoles do not cancel due to the bent shape. This large dipole moment makes water: a polar solvent (dissolves ionic compounds), strongly attracted to other polar molecules (hydrogen bonding), strongly absorbent of microwave radiation (cooking), and responsible for water's high boiling point ($100°$C) compared to similar non-polar molecules.
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