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ChemistryAmines
Arrange the following compounds in order of decreasing basicity:
I. $N$-ethylethanamine (diethylamine)
II. Ethanamine (ethylamine)
III. $N$-methylaniline
IV. Benzenamine (aniline)
Options
1
I > II > III > IV
2
II > I > III > IV
3
I > II > IV > III
4
IV > III > II > I
Correct Answer
I > II > III > IV
Solution
1

Factors: (+I) alkyl groups increase basicity. (-R) aromatic ring delocalises lone pair → decreases basicity.

Aliphatic amines >> Aromatic amines (large difference)

Among aliphatic (aqueous): 2° > 1° (more alkyl groups, better solvation of cation)

2

Ranking: Diethylamine (2° aliph.) > Ethylamine (1° aliph.) > N-methylaniline (2° arom.) > Aniline (1° arom.)

$$\boxed{I > II > III > IV}$$
2° aliphatic > 1° aliphatic >> 2° aromatic > 1° aromatic
Key: aryl group delocalises N lone pair → much less basic
Theory: Amines
1. Basicity of Amines — Key Factors

Basicity of amines measured by $pK_b$ (or $pK_a$ of conjugate acid, the ammonium salt $RNH_3^+$). Higher $pK_a$ of ammonium = more basic amine. Key factors affecting basicity: (1) Inductive effect (+I) of alkyl groups: alkyl groups donate electrons to N → increased electron density → better proton acceptance → more basic. (2) Resonance (-R) of aryl groups: benzene ring delocalises N lone pair through resonance → reduced electron density on N → less basic. Effect is large: aniline ($pK_a = 4.6$) vs ethylamine ($pK_a = 10.6$). (3) Solvation of ammonium ion in aqueous solution: larger cation (more alkyl groups) may be less well solvated → affects aqueous basicity. This is why tertiary aliphatic amine is slightly less basic than secondary in water despite having most alkyl groups. (4) Steric effect: bulky groups around N may hinder approach of proton. (5) Hybridisation: sp3 N is more basic than sp2 or sp N (electrons held less tightly in sp3 orbital). Pyrrole (N sp2, lone pair in aromatic ring) is non-basic.

2. Basicity Order in Aqueous Solution vs Gas Phase

Gas phase basicity increases monotonically with alkyl substitution: $R_3N > R_2NH > RNH_2 > NH_3$. Each added alkyl group donates electrons via +I effect. Aqueous solution: different! Secondary amine is most basic (for short alkyl chains). Tertiary is less basic than secondary because: ammonium ion $R_3NH^+$ is poorly solvated (3 bulky alkyl groups block water access to N-H) → less stabilisation of protonated form → less basic. Order in water (for methylamines): $(CH_3)_2NH > CH_3NH_2 > (CH_3)_3N > NH_3$. For ethylamines (this question): $(C_2H_5)_2NH > C_2H_5NH_2 > (C_2H_5)_3N > NH_3$. NEET questions on amine basicity: remember that the aqueous order is 2° > 1° > 3° > NH3 for simple alkylamines (for small alkyl groups). For larger alkyl groups: steric effect on solvation becomes more pronounced.

3. Aromatic Amines — Reduced Basicity

In aniline (PhNH2), the N lone pair is conjugated with benzene ring: $\text{Ph-NH}_2 \leftrightarrow \text{Ph}^- \text{NH}_2^+$ resonance structures. This partial positive charge on N reduces electron availability → weaker base. pKa values of ammonium salts: NH3: 9.25. CH3NH2: 10.6. (CH3)2NH: 10.7. (CH3)3N: 9.8. PhNH2 (aniline): 4.6. PhN(CH3)H (N-methylaniline): 4.85. Ph2NH (diphenylamine): 0.8. Ph3N (triphenylamine): essentially non-basic. Each additional phenyl group further delocalises lone pair → drastically reduces basicity. Electron-withdrawing groups on ring (NO2, CN) further reduce basicity: p-nitroaniline pKa = 1.0. Electron-donating groups (CH3, OCH3, OH) increase: p-methoxyaniline pKa = 5.3. o-toluidine pKa = 4.44. 2,4-dinitroaniline: pKa = -4.5 (extremely weak base).

4. Effect of Substituents on Amine Basicity

Electron-donating groups (EDG): +I alkyl, +R OH, OCH3 → increase electron density on N → increase basicity. Electron-withdrawing groups (EWG): -I halogens, NO2, CN, COOH → decrease electron density → decrease basicity. For N-alkyl aromatic amines: +I of alkyl on N partially offsets -R of phenyl → N-methylaniline slightly more basic than aniline. For amines on ring: EDG on ring → more electron density → ring donates more to N? No: EDG on ring (para) increases electron density in ring → actually decreases the tendency of ring to accept N lone pair → N lone pair less delocalised → more available → more basic. So p-methoxyaniline > aniline > p-nitroaniline. This is because: when ring is electron-rich (EDG), the negative resonance delocalisation from N to ring is less favourable → N retains more electron density.

5. Heterocyclic Amines

Pyridine (N in ring, sp2, lone pair in sp2 orbital in plane of ring, NOT in p-orbital): basic ($pK_a = 5.2$). Lone pair available for protonation, not in aromatic system. Pyrrole (N in ring, sp2, lone pair in p-orbital = part of aromatic 6π system): essentially non-basic ($pK_a \approx -3.8$ — lone pair delocalised into aromatic ring, unavailable for protonation). Imidazole: both pyridine-like N (basic, $pK_a = 7.0$) and pyrrole-like N (non-basic). In proteins: histidine has imidazole side chain — $pK_a \approx 6$, important for enzyme catalysis at physiological pH. Quinoline ($pK_a = 4.9$, less basic than pyridine due to extended delocalisation). Piperidine ($pK_a = 11.2$, sp3 N, most basic of common ring amines).

6. Reactions of Amines — Overview

Basic character: react with acids to form ammonium salts (RNH2 + HCl → RNH3+Cl-). Nucleophilic character: react with alkyl halides (SN2, alkylation), acyl halides (amide formation), aldehydes/ketones (imine formation), CO2 (carbamate), NO2+ (nitrosation). Acylation: RNH2 + (CH3CO)2O → RNHCOCH3 (acetamide) + CH3COOH. Protection of amine: acetylation. Benzoylation (Schotten-Baumann, using NaOH). Hinsberg reaction: primary and secondary amines react differently with sulfonyl chloride. Primary amine product is soluble in NaOH (has N-H, acidic). Secondary amine product is insoluble (no N-H). Tertiary amine does not react. Used to distinguish 1°, 2°, 3° amines. Carbylamine reaction: primary amine + CHCl3 + KOH → isocyanide (foul-smelling). Specific to primary amines only.

7. Amines in Industry and Biology

Industrial amines: Aniline: precursor to dyes (azo dyes, indigo), pharmaceuticals (paracetamol synthesis), polyurethanes (MDI, TDI). Ethylamine: in pharmaceuticals, agricultural chemicals. Hexamethylenediamine + adipic acid → nylon-6,6. Aminoacids: 20 amino acids have amino group. pKa of amino group ≈ 9-10, carboxyl ≈ 2-3 → zwitterion at neutral pH. Neurotransmitters: dopamine, serotonin (5-HT), norepinephrine, epinephrine, histamine, GABA — all amines. Drugs: amphetamine, cocaine, morphine, atropine — all contain amine groups. The amine group can be protonated at physiological pH (positively charged) → important for receptor binding and drug transport across membranes. Drug design: pKa of amine affects membrane permeability (neutral form crosses membranes) and target binding.

8. Preparation of Amines

From nitro compounds: ArNO2 + Fe/HCl → ArNH2 (aniline from nitrobenzene, industrial method). Also: Sn/HCl, Zn/NH4Cl, H2/Pd catalyst. From nitriles: RCN + H2/Ni → RCH2NH2 (primary amine, one C longer). LiAlH4 also reduces nitriles. Gabriel synthesis: phthalimide + KOH → potassium phthalimide + RX (SN2) → N-alkylphthalimide → hydrolysis (H2O/OH-) → primary amine + phthalic acid. Makes primary amines exclusively (without secondary/tertiary contamination). Hofmann bromamide reaction: RCONH2 + Br2 + NaOH → RNH2 (primary amine, one C SHORTER). Mechanism: N-bromination → ring closure → isocyanate intermediate → hydrolysis. Schmidt reaction: RCOOH + HN3 + H2SO4 → RNH2 (one C shorter). Beckmann rearrangement: ketoxime + H2SO4 → amide.

Frequently Asked Questions
1. Why is the aqueous basicity order for alkylamines 2° > 1° > 3°?
This apparently paradoxical order (secondary more basic than tertiary despite fewer alkyl groups) is explained by the opposing effects of: (1) Inductive effect: 3 alkyl groups > 2 > 1 in donating electrons to N (predicts 3° > 2° > 1°). (2) Solvation of ammonium ion: (CH3)3NH+ has 3 large methyl groups blocking approach of water molecules → poor solvation → less stabilisation of protonated form → less basic. (CH3)2NH2+ has better solvation (2 N-H protons available, less steric hindrance). For small methylamines: solvation effect almost exactly counteracts +I effect → (CH3)2NH > CH3NH2 > (CH3)3N by small margin. Gas phase (no solvation): basicity increases monotonically: (CH3)3N > (CH3)2NH > CH3NH2 > NH3.
2. How does resonance reduce basicity of aniline?
In aniline: N lone pair (in p-orbital perpendicular to benzene plane) overlaps with benzene π system. Five resonance structures show that N has partial positive charge in some structures. The resonance hybrid has N with reduced electron density. When aniline is protonated (anilinium ion formed), the positive charge on N disrupts the resonance delocalisation because N+ cannot donate lone pair to ring anymore → ring aromaticity maintained but stabilisation from conjugation lost. The trade-off: conjugation stabilises neutral aniline significantly but destabilises the protonated form → equilibrium favours unprotonated form → weak base. For comparison, water pKa = -1.7, ammonia = 9.25, aniline = 4.6.
3. What is the Hinsberg test and how does it distinguish amines?
Hinsberg test uses benzenesulfonyl chloride (PhSO2Cl) in NaOH. Primary amine: reacts to form sulfonamide PhSO2NHR → has acidic N-H → dissolves in NaOH (forms PhSO2NR-Na+). On acidification: precipitate reforms. Secondary amine: reacts to form PhSO2NR2 → no N-H → insoluble in NaOH. Tertiary amine: does not react (N too hindered/no N-H). Sequence: (1) Add PhSO2Cl + NaOH → observe. (2) If solid forms, acidify → 1° if dissolves (sulfonamide was soluble in base), 2° if insoluble stays. No reaction → tertiary. This classical test has largely been replaced by spectroscopic methods (NMR, IR) in modern labs, but remains important for NEET.
4. Why does electron-withdrawing group on benzene ring reduce basicity of aniline further?
Electron-withdrawing groups (NO2, CN, CHO, COOH) on benzene ring reduce electron density in the ring. This makes the ring more electron-deficient → more tendency to accept electrons from N lone pair → stronger resonance delocalisation of N lone pair into ring → N has even less electron density → even weaker base. p-nitroaniline ($pK_a = 1.0$) vs aniline ($pK_a = 4.6$): NO2 group withdraws electrons both by resonance (from para position to NO2) and induction → massive reduction in basicity. 2,4-dinitroaniline ($pK_a = -4.5$): two NO2 groups → essentially not basic at all. o and p positions show stronger effect than m (resonance operates at o and p positions only). EDG (CH3, OCH3) at p position increase electron density in ring → less resonance delocalisation of N → N is slightly more basic.
5. How are amines important in drug design?
Most drugs are weak bases (have basic nitrogen groups) for several reasons: (1) Oral bioavailability: amine group can be protonated at stomach pH (pH ~2) → ionic, water soluble → absorbed. At intestinal pH (~7): neutral, membrane-soluble → crosses epithelial cells → enters blood. (2) Target binding: protonated amine (R-NH3+) forms ionic bond with negatively charged residues (Asp, Glu) in enzyme/receptor active sites. (3) Blood-brain barrier: only neutral (unprotonated) amine crosses. pKa controls fraction that can enter brain. (4) Metabolism: amine groups are sites for Phase I metabolism (N-oxidation, N-dealkylation by CYP enzymes) → affects half-life. Examples: morphine (two amines, pKa 9.9 and 6.1), adrenaline/epinephrine (amine pKa ~9.5), histamine (two amines, pKa 5.8 and 9.7).
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