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PhysicsAlternating Current
An ac circuit contains a resistance of 1 kΩ, a capacitor of 0·1 μF and an inductor of 1 mH connected in series. The resonance frequency of the circuit is approximately :
Options
1
10·1 kHz
2
20·7 kHz
3
15·9 kHz
4
13·5 kHz
Correct Answer
Option 3 : 15·9 kHz
Step-by-Step Solution
1

Given: L = 1 mH = 10⁻³ H, C = 0·1 μF = 10⁻⁷ F, R = 1 kΩ (R doesn't affect resonance frequency)

2

Resonance frequency formula:

f꜀ = 1 / (2π√LC)

f꜀ = 1 / (2π × √(10⁻³ × 10⁻⁷))

f꜀ = 1 / (2π × √10⁻¹⁰)

f꜀ = 1 / (2π × 10⁻⁵)

f꜀ = 10⁵ / (2π) Hz

3

f꜀ = 10⁵ / (2 × 3·14159) = 10⁵ / 6·2832 ≈ 15,915 Hz ≈ 15·9 kHz

Note: 50/π kHz = 50/3·14159 ≈ 15·92 kHz ✓

f꜀ = 1/(2π√LC) = 10⁵/2π Hz ≈ 15·9 kHz

R does NOT affect resonance frequency

Theory: Series RLC Circuit & Resonance
1. Impedance of Series RLC Circuit

In a series RLC circuit, the total opposition to AC current is called impedance Z. It combines resistance R, inductive reactance X_L = ωL, and capacitive reactance X_C = 1/(ωC). The net reactance is X = X_L − X_C. Total impedance: Z = √(R² + (X_L − X_C)²). The phase angle between voltage and current: tan φ = (X_L − X_C)/R. Current lags voltage when X_L > X_C (inductive circuit), leads when X_C > X_L (capacitive circuit).

2. Resonance Condition

Resonance occurs when X_L = X_C, i.e., ωL = 1/(ωC). This gives the resonant angular frequency ω꜀ = 1/√(LC) and resonant frequency f꜀ = ω꜀/2π = 1/(2π√LC). At resonance: impedance is minimum and equal to R alone (Z_min = R), current is maximum (I_max = V/R), the circuit is purely resistive (power factor = 1, φ = 0), and the voltages across L and C are equal and opposite — they cancel each other out, but individually can be much larger than the source voltage (voltage magnification).

3. Quality Factor (Q-factor)

Q-factor measures the sharpness of resonance — how selective the circuit is. Q = ω꜀L/R = 1/(ω꜀CR) = (1/R)√(L/C). A high Q means sharp resonance (narrow bandwidth, selective) — used in radio tuning. A low Q means broad resonance (less selective). Bandwidth Δω = ω꜀/Q = R/L. The frequencies at which power falls to half the maximum (half-power points) are: ω₁ = ω꜀ − R/(2L) and ω₂ = ω꜀ + R/(2L). In this problem: Q = ω꜀L/R = (10⁵ × 10⁻³)/(1000) = 100/1000 = 0·1 (low Q, broad resonance).

4. Voltage Across Each Component at Resonance

📌 V_R = IR (in phase with current) — equals source voltage V at resonance

📌 V_L = IX_L = IωL (leads current by 90°) — can exceed source voltage!

📌 V_C = IX_C = I/(ωC) (lags current by 90°) — can exceed source voltage!

📌 V_L = V_C at resonance, so they cancel → net reactive voltage = 0

📌 V_L/V = V_C/V = Q (Q-factor = voltage magnification ratio)

📌 This is why capacitors/inductors can have high voltages even with small source voltage!

5. Power in AC Circuits

Instantaneous power P = V·I varies with time in AC. Average (real) power = V_rms × I_rms × cos φ, where cos φ is the power factor. At resonance: φ = 0, cos φ = 1, all power is dissipated in R (maximum power transfer). Purely inductive (φ = 90°) or purely capacitive (φ = −90°) circuits: cos φ = 0, no real power consumed — only reactive power (stored and returned each cycle). Wattless current: the component of current 90° out of phase with voltage does no work.

6. Applications of Resonance

Series resonance is used in radio and TV tuning circuits — by varying C (or L), the resonant frequency is tuned to match the desired station's frequency, giving maximum current (and hence signal) only at that frequency. The selectivity (ability to distinguish stations) depends on Q-factor. Parallel resonance (anti-resonance) is used in filter circuits and oscillators. MRI (Magnetic Resonance Imaging) uses nuclear magnetic resonance — a completely different type but same concept.

7. Comparison: Series vs Parallel Resonance

📌 Series resonance: Z minimum = R, current maximum, voltage magnification = Q

📌 Parallel resonance: Z maximum = L/(CR), current minimum, current magnification = Q

📌 Both: resonant frequency f꜀ = 1/(2π√LC) (same formula)

📌 Series used for: current amplification, tuning, band-pass filters

📌 Parallel used for: impedance matching, oscillators, band-stop filters

8. Transformers and Mutual Inductance

A transformer works on the principle of mutual inductance — changing current in one coil (primary) induces EMF in another coil (secondary). V_s/V_p = N_s/N_p = I_p/I_s (for ideal transformer). Step-up transformer: N_s > N_p → increases voltage, decreases current. Step-down: N_s < N_p → decreases voltage, increases current. Power is conserved in ideal transformers: V_p I_p = V_s I_s. Real transformers have losses: copper loss (I²R in windings), iron loss (eddy currents + hysteresis in core). Laminating the core reduces eddy current losses.

Frequently Asked Questions
1. Why doesn't R affect resonance frequency?
Resonance condition is X_L = X_C, i.e., ωL = 1/(ωC). This gives ω꜀ = 1/√(LC). R appears nowhere in this equation. R affects: (1) Maximum current at resonance (I_max = V/R — higher R means lower current). (2) Q-factor (Q = ω꜀L/R — higher R means lower Q, broader resonance). (3) Power dissipation. But the frequency at which resonance occurs depends only on L and C.
2. How to quickly calculate resonance frequency?
Step 1: Convert L and C to SI units (H and F). Step 2: Calculate LC. Step 3: Take √(LC). Step 4: f꜀ = 1/(2π√LC). Shortcut: f꜀ = 1/(2π) × 10^(−½ × log(LC)). Here LC = 10⁻³ × 10⁻⁷ = 10⁻¹⁰, √(10⁻¹⁰) = 10⁻⁵. So f꜀ = 10⁵/(2π) ≈ 10⁵/6·28 ≈ 15,900 Hz = 15·9 kHz.
3. What is Q-factor physically?
Q-factor = quality factor = ω꜀L/R = (1/R)√(L/C). Physically: Q = (energy stored)/(energy dissipated per radian). High Q → more energy stored, less dissipated → sharper resonance peak → more selective circuit. Q also equals voltage magnification at resonance: V_L = V_C = Q×V_source. In this problem Q = ω꜀L/R = (2π×15900×10⁻³)/1000 = 0·1 — very low Q means broad resonance.
4. Can voltage across L or C exceed source voltage?
Yes! This is voltage magnification. At resonance, V_L = V_C = Q×V_source. If Q = 100 and V_source = 10V, then V_L = V_C = 1000V! This can be dangerous — capacitors and inductors can develop very high voltages even with small source voltage. This is why high-voltage equipment uses resonance for voltage multiplication. However, V_L and V_C are 180° out of phase, so they cancel and don't appear as high voltage across the source.
5. What is bandwidth in series RLC circuit?
Bandwidth = range of frequencies over which power ≥ P_max/2 (half-power bandwidth). Δf = f꜀/Q = R/(2πL). Half-power frequencies: f₁ = f꜀ − Δf/2 and f₂ = f꜀ + Δf/2. Narrow bandwidth (high Q) → more selective. Wide bandwidth (low Q) → less selective but more stable. AM radio needs ~10 kHz bandwidth; FM radio needs ~200 kHz bandwidth.
6. What happens below and above resonance frequency?
Below f꜀: X_C > X_L → circuit is capacitive → current leads voltage → φ < 0. Above f꜀: X_L > X_C → circuit is inductive → current lags voltage → φ > 0. At f꜀: X_L = X_C → circuit is purely resistive → current in phase with voltage → φ = 0 → maximum current and power.
7. How do radio tuning circuits work using resonance?
A radio antenna receives signals from all stations simultaneously. Each station broadcasts at a different frequency. The tuning circuit (variable C in series/parallel with L) is adjusted so that the resonant frequency matches the desired station. At resonance, that station's signal produces maximum current (voltage) — all other frequencies produce much less current. The selectivity (how well one station is isolated from neighbours) depends on Q-factor of the tuning circuit.
8. What is the significance of power factor = 1 at resonance?
Power factor cos φ = R/Z. At resonance Z = R, so cos φ = 1. This means all electrical power supplied by the source is dissipated as heat in R — no power is wasted in reactive components (L and C store and return energy but don't consume it). Power factor = 1 is ideal for power transmission. In industrial settings, low power factor wastes energy and requires larger cables — capacitor banks are added to correct it.
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