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PhysicsCurrent Electricity
A resistor is connected to a battery of 12 V emf and internal resistance 2 Ω. If the current in the circuit is 0·6 A, the terminal voltage of the battery is :
Options
1
10 V
2
1·2 V
3
12 V
4
10·8 V
Correct Answer
Option 4 : 10·8 V
Step-by-Step Solution
1

Given values:

EMF (\(\varepsilon\)) = 12 V

Internal resistance (\(r\)) = 2 Ω

Current (\(I\)) = 0·6 A

2

Formula for Terminal Voltage:

When a battery supplies current to an external circuit, the terminal voltage is:

$$V = \varepsilon - I \times r$$

3

Calculate voltage drop across internal resistance:

$$I \times r = 0.6 \times 2 = 1.2 \text{ V}$$

This 1.2 V is lost as heat inside the battery itself.

4

Calculate Terminal Voltage:

$$V = 12 - 1.2 = \mathbf{10.8 \text{ V}}$$

So the terminal voltage = 10.8 V

Theory: EMF, Internal Resistance & Terminal Voltage
1. What is Electromotive Force (EMF)?

Electromotive force (EMF), denoted by ε (epsilon), is NOT actually a force — it is a potential difference (measured in Volts). EMF is defined as the work done by the battery per unit charge in driving the charge through the complete circuit, including through the battery itself. In simpler terms, EMF is the maximum voltage a battery can provide when no current is being drawn from it (open circuit condition).

EMF arises from the conversion of some other form of energy (chemical, mechanical, solar, etc.) into electrical energy inside the source. In a chemical battery, the chemical reactions between the electrodes and the electrolyte create a potential difference that drives the current. The EMF of a cell depends on the nature of the electrolyte and electrode material, not on the size or shape of the cell.

2. What is Internal Resistance?

Every real battery or cell has some resistance to the flow of current within itself, called internal resistance (r). This arises from the resistance of the electrolyte and the electrodes inside the cell. Even though we cannot see it externally, internal resistance behaves exactly like a series resistor connected inside the battery.

As a battery gets older or discharged, its internal resistance increases. A freshly charged battery has low internal resistance, allowing it to deliver higher current. When a battery "dies," it often still has some EMF remaining, but its internal resistance has increased so much that the terminal voltage drops significantly under load.

3. Terminal Voltage — The Key Concept

Terminal voltage (V) is the actual voltage available at the terminals of the battery when current is flowing. It is always different from EMF when current flows, because of the voltage drop across the internal resistance.

\(V = \varepsilon - Ir\)   (During Discharging)

\(V = \varepsilon + Ir\)   (During Charging)

\(V = \varepsilon\)   (Open Circuit — No current)

This is the single most important set of formulas for this topic in NEET. Memorise all three cases:

📌 Discharging: V < ε — terminal voltage is less than EMF

📌 Charging: V > ε — terminal voltage is greater than EMF

📌 Open Circuit: V = ε — no current, no internal drop

4. Kirchhoff's Voltage Law Application

The terminal voltage formula can also be derived using Kirchhoff's Voltage Law (KVL). Going around the circuit loop: EMF − voltage drop across internal resistance − voltage across external resistance = 0. This gives ε − Ir − IR = 0, so IR = ε − Ir. Since IR = V (terminal voltage), we get V = ε − Ir.

The current in the circuit can also be written as:

\(I = \dfrac{\varepsilon}{R + r}\)

where R is the external resistance and r is the internal resistance. This is the most fundamental equation for a circuit with a real battery.

5. Power Analysis in a Battery Circuit

The total power delivered by the EMF source is P_total = εI. This total power is split between the external circuit and the internal resistance. Power delivered to external circuit: P_external = I²R = VI. Power lost inside battery: P_internal = I²r. Conservation of energy gives: εI = I²R + I²r, or ε = IR + Ir, which is consistent with our KVL equation.

The efficiency of the battery (ratio of useful power to total power) is:

\(\eta = \dfrac{P_{external}}{P_{total}} = \dfrac{I^2 R}{\varepsilon I} = \dfrac{R}{R+r}\)

For maximum efficiency, R >> r. For maximum power transfer (different from efficiency), R = r — this is the condition of maximum power transfer theorem.

6. Grouping of Cells

In NEET, problems on grouping of cells are very common. For n cells each of EMF ε and internal resistance r:

📌 Series grouping: Total EMF = nε, Total internal resistance = nr

📌 Parallel grouping: Total EMF = ε, Total internal resistance = r/n

📌 Mixed grouping (m rows, n columns): EMF = nε, r_total = nr/m

Series grouping is preferred when external resistance is large. Parallel grouping is preferred when external resistance is small (to match internal resistance for better efficiency). Mixed grouping gives maximum current when R = nr/m (internal = external resistance condition).

7. Measuring EMF and Internal Resistance

A potentiometer is used to measure the exact EMF of a cell without drawing any current, because at balance point the galvanometer shows zero deflection meaning no current flows through the cell branch. Since I = 0, V = ε exactly. A voltmeter, on the other hand, always draws a small current and hence reads terminal voltage slightly less than EMF.

To find internal resistance experimentally: measure terminal voltage V with external resistance R. Then r = (ε − V)/I = (ε − V)R/V. This can be rearranged to give a straight line equation, allowing r to be found from a graph of V vs I.

8. Common NEET Mistakes in This Topic

⚠️ Confusing EMF with terminal voltage — EMF is the source, terminal voltage is what you actually get.

⚠️ Forgetting to subtract the internal resistance drop when finding terminal voltage.

⚠️ Using V = IR where R is only external resistance to find current — correct formula is I = ε/(R+r).

⚠️ In charging problems, adding Ir instead of subtracting when finding terminal voltage — remember V = ε + Ir for charging.

Frequently Asked Questions
1. What is the formula for terminal voltage?
V = ε − Ir during discharging, where ε is EMF, I is current, and r is internal resistance. In this problem: V = 12 − (0.6 × 2) = 10.8 V.
2. Why is terminal voltage less than EMF?
Because some voltage is dropped across the internal resistance of the battery itself. This drop = Ir = 0.6 × 2 = 1.2 V. So 1.2 V is "wasted" inside the battery as heat.
3. What is terminal voltage in an open circuit?
In open circuit, I = 0 so Ir = 0. Therefore terminal voltage = EMF. This is why a voltmeter connected to a battery with no external circuit reads close to the EMF value.
4. What is the external resistance in this problem?
Total resistance = ε/I = 12/0.6 = 20 Ω. External resistance R = Total − r = 20 − 2 = 18 Ω. We can verify: V = IR = 0.6 × 18 = 10.8 V ✓
5. When is terminal voltage greater than EMF?
When the battery is being charged. An external source drives current into the battery, so V = ε + Ir > ε. The terminal voltage you apply must exceed the battery's EMF to force current through it.
6. What is the power lost in the internal resistance here?
P = I²r = (0.6)² × 2 = 0.36 × 2 = 0.72 W. This 0.72 W is lost as heat inside the battery and reduces its efficiency.
7. How does internal resistance affect battery life?
Higher internal resistance means more energy is wasted as heat inside the battery for the same current. This drains the battery faster and heats it up. Old and worn-out batteries have higher internal resistance, which is why they drain quickly even under light loads.
8. Why can't we measure EMF with a voltmeter?
A voltmeter draws a small current. When current flows, terminal voltage = ε − Ir < ε. So a voltmeter always reads slightly less than the true EMF. A potentiometer is used for accurate EMF measurement since it draws zero current at balance.
9. What happens to terminal voltage as current increases?
As current increases, the drop Ir increases, so terminal voltage V = ε − Ir decreases. If you short-circuit a battery (R = 0), maximum current I = ε/r flows and terminal voltage drops to nearly zero.
10. What is the condition for maximum power transfer?
Maximum power is transferred to the external resistance when R = r (external resistance equals internal resistance). At this condition, terminal voltage = ε/2 and maximum power P_max = ε²/4r. Note: this is NOT the condition for maximum efficiency.
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