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ChemistryQualitative Analysis
Match the cation groups in qualitative analysis with their reagents/conditions:
A. Group I (Ag⁺, Pb²⁺, Hg₂²⁺)
B. Group II (Cu²⁺, Pb²⁺, Bi³⁺, Cd²⁺, Sn²⁺, As³⁺, Sb³⁺)
C. Group III (Al³⁺, Fe³⁺, Cr³⁺)
D. Group IV (Zn²⁺, Ni²⁺, Co²⁺, Mn²⁺)
Reagents: I. NH₄OH + (NH₄)₂S, II. H₂S in NH₃, III. Dilute HCl, IV. H₂S in HCl
Options
1
A-III, B-IV, C-I, D-II
2
A-IV, B-III, C-I, D-II
3
A-III, B-I, C-IV, D-II
4
A-II, B-IV, C-III, D-I
Correct Answer
A-III, B-IV, C-I, D-II
Solution
1

A. Group I cations (Ag⁺, Pb²⁺, Hg₂²⁺) precipitate with dilute HCl → III

B. Group II (Cu²⁺, Bi³⁺ etc.) precipitate with H₂S in acidic HCl → IV

2

C. Group III (Al³⁺, Fe³⁺, Cr³⁺) precipitate as hydroxides with NH₄OH → I

D. Group IV (Zn²⁺, Ni²⁺, Co²⁺) precipitate with H₂S in NH₃ → II

Answer: A-III, B-IV, C-I, D-II

Group I = HCl | Group II = H₂S/HCl | Group III = NH₄OH | Group IV = H₂S/NH₃
Theory: Qualitative Analysis
1. Systematic Qualitative Analysis — Overview

Qualitative inorganic analysis (classical wet chemistry) identifies cations and anions in an unknown salt. Cations are separated into groups based on their precipitating reagent. The groups for cations (Sulphide group method): Group I (HCl group): Ag⁺, Pb²⁺, Hg₂²⁺ — precipitate as chlorides with dilute HCl. Group II (H₂S in acid): Cu²⁺, Pb²⁺, Bi³⁺, Cd²⁺, Sn²⁺/Sn⁴⁺, As³⁺/As⁵⁺, Sb³⁺ — precipitate as sulfides in dilute HCl (acidic medium). Group III (NH₄OH): Al³⁺, Fe³⁺, Cr³⁺ — precipitate as hydroxides. Co²⁺, Ni²⁺, Mn²⁺, Zn²⁺ are not precipitated (their hydroxides are more soluble). Group IV (H₂S in NH₃): Zn²⁺, Ni²⁺, Co²⁺, Mn²⁺ — precipitate as sulfides in alkaline medium. Group V ((NH₄)₂CO₃): Ba²⁺, Sr²⁺, Ca²⁺ — precipitate as carbonates. Group VI (no reagent): Mg²⁺, Na⁺, K⁺, NH₄⁺ — soluble group, detected by specific flame tests or precipitation reactions.

2. Chemistry of Group I Separation

Reagent: dilute HCl. Precipitates: AgCl (white, curdy, insoluble), PbCl₂ (white, slightly soluble in cold water, dissolves in hot water — used to confirm Pb²⁺), Hg₂Cl₂ (calomel, white, turns black with NH₃ due to disproportionation: Hg₂Cl₂ + 2NH₃ → Hg(NH₂)Cl↓(white) + Hg↓(black) + NH₄Cl). Confirmatory tests: AgCl dissolves in NH₃ (forms [Ag(NH₃)₂]⁺) but PbCl₂ does not → distinguishes Ag⁺ from Pb²⁺. AgCl in NH₃ + acidify → white precipitate returns. AgCl + KI → AgI (yellow) — more insoluble. Ksp values: AgCl = 1.8×10⁻¹⁰, AgBr = 5×10⁻¹³, AgI = 8.5×10⁻¹⁷ (decreasing solubility). PbSO₄ (white) also precipitates with dilute H₂SO₄. Lead stays in both Group I and Group II.

3. Role of H₂S and pH in Group Separation

H₂S in water: $H_2S \rightleftharpoons H^+ + HS^- \rightleftharpoons 2H^+ + S^{2-}$. Overall: $K = [H^+]^2[S^{2-}]/[H_2S] \approx 10^{-21}$. At pH = 0 (1M HCl): $[S^{2-}] = 10^{-21}/(1)^2 = 10^{-21}$ M. Only very insoluble sulfides (Ksp < 10⁻²⁰) precipitate → Group II (CuS Ksp = 10⁻³⁶, Bi₂S₃ Ksp = 10⁻⁹⁹). At pH = 9 (ammoniacal): $[S^{2-}] \approx 10^{-21}/(10^{-9})^2 = 10^{-3}$ M. Less insoluble sulfides also precipitate → Group IV (ZnS Ksp = 10⁻²³, NiS Ksp = 10⁻²¹, MnS Ksp = 10⁻¹³). This pH control is the fundamental principle separating Group II from Group IV.

4. Flame Tests for Group VI Cations

Flame tests identify alkali metal ions and alkaline earth metals (Groups V and VI) because their electrons excited by flame emit characteristic wavelengths. Li⁺: crimson red (670 nm). Na⁺: golden yellow (589 nm, very intense — masks other colours). K⁺: violet/lilac (767 nm). Ca²⁺: brick red (622 nm). Sr²⁺: crimson red (606 nm). Ba²⁺: pale green (554 nm). Cu²⁺: blue-green (513 nm). Pb²⁺: pale blue (not diagnostic). Technique: clean platinum wire (or nichrome), dip in sample dissolved in HCl, hold in non-luminous bunsen flame. View K⁺ through blue cobalt glass (filters yellow Na⁺ light). Spectroscope: identifies elements more precisely than naked eye. Atomisation and electronic excitation in flame → emission spectrum. Modern: ICP-OES (Inductively Coupled Plasma Optical Emission Spectrometry) does this quantitatively for ppb concentrations.

5. Anion Analysis

Dilute H₂SO₄ group: CO₃²⁻ (CO₂, limewater test), S²⁻ (H₂S, smell/lead acetate paper), SO₃²⁻ (SO₂, smell/potassium permanganate decolourise), NO₂⁻ (brown fumes). Concentrated H₂SO₄ group: Cl⁻ (HCl gas, white fumes with NH₃), Br⁻ (HBr + brown Br₂), I⁻ (HI + violet I₂ vapour), NO₃⁻ (brown fumes of NO₂), CH₃COO⁻ (vinegar smell). Silver nitrate test: Cl⁻ → AgCl (white, soluble in NH₃). Br⁻ → AgBr (pale yellow, soluble in conc. NH₃). I⁻ → AgI (yellow, insoluble in NH₃). Barium chloride test: SO₄²⁻ → BaSO₄ (white precipitate, insoluble in HCl). Ferric chloride test: CNS⁻ → blood-red [Fe(CNS)]²⁺. CH₃COO⁻ → iron acetate (reddish brown, fruity smell of ester on heating with H₂SO₄).

6. Solubility Product and Precipitation

Solubility product $K_{sp} = [M^{n+}][A^{m-}]$ for sparingly soluble salt MA. For $M_aA_b$: $K_{sp} = [M]^a[A]^b$. Condition for precipitation: ionic product $Q > K_{sp}$. When $Q = K_{sp}$: saturated solution (equilibrium). $Q < K_{sp}$: unsaturated, no precipitate. Common ion effect: adding a common ion decreases solubility (Le Chatelier). Example: AgCl in 0.1 M NaCl: $[Ag^+] = K_{sp}/[Cl^-] = 1.8\times10^{-10}/0.1 = 1.8\times10^{-9}$ M. Compared to AgCl in pure water: $[Ag^+] = \sqrt{K_{sp}} = 1.34\times10^{-5}$ M. Solubility decreased by factor 7400. Selective precipitation: by controlling anion concentration, separate cations. Fractional precipitation: adding precipitating reagent gradually — less soluble salt precipitates first.

7. Confirmatory Tests for Common Ions

Fe³⁺: KSCN → blood-red [Fe(SCN)]²⁺. K₄[Fe(CN)₆] → Prussian blue Fe₄[Fe(CN)₆]₃. Cu²⁺: NH₃ → deep blue [Cu(NH₃)₄]²⁺. K₄[Fe(CN)₆] → chocolate-brown CuFe(CN)₆ precipitate. Al³⁺: aluminon test → red lake. NH₃ + aluminon solution → Al(OH)₃ adsorbs aluminon. Flame test: not characteristic. Pb²⁺: K₂CrO₄ → yellow PbCrO₄ precipitate. H₂S → black PbS. KI → bright yellow PbI₂. Mn²⁺: sodium bismuthate (NaBiO₃) in HNO₃ → MnO₄⁻ (purple) oxidation confirms Mn. HNO₃ + Mn²⁺ + ammonium persulphate → purple MnO₄⁻. Zn²⁺: K₄[Fe(CN)₆] → white ZnK₂[Fe(CN)₆]. Sodium hydroxide → white Zn(OH)₂ dissolves in excess NaOH (amphoteric → [Zn(OH)₄]²⁻). NH₃ → white Zn(OH)₂ dissolves in excess → [Zn(NH₃)₄]²⁺.

8. Modern Analytical Methods vs Classical

Classical qualitative analysis (wet chemistry): historically important, still taught for conceptual understanding. Time-consuming, requires skilled analyst, uses hazardous H₂S gas. Modern alternatives: ICP-OES (Inductively Coupled Plasma Optical Emission Spectrometry): simultaneous determination of 70+ elements at ppb levels in minutes. Sample dissolved, passed through plasma (10,000 K), emitted light analysed. ICP-MS (Mass Spectrometry): ppt sensitivity, isotopic information. XRF (X-ray fluorescence): non-destructive elemental analysis of solid surfaces. AAS (Atomic Absorption Spectroscopy): highly selective, one element at a time, ppm-ppb sensitivity. For NEET: understand the classical group analysis scheme, reagents, chemistry. The conceptual understanding (why H₂S separates Group II from IV, why pH matters, why flame tests work) is more important than memorisation. The group separation scheme also illustrates: Ksp, common ion effect, solubility equilibria, complex ion formation — all important topics.

Frequently Asked Questions
1. What is the chemistry behind Group II vs Group IV separation using H₂S?
H₂S ionisation equilibrium: $H_2S \rightleftharpoons 2H^+ + S^{2-}$. $K = [H^+]^2[S^{2-}] = 10^{-21}$. Solving: $[S^{2-}] = 10^{-21}/[H^+]^2$. In acid (1M HCl, [H⁺]=1): $[S^{2-}] = 10^{-21}$ M. Group II sulfides (CuS Ksp ≈ 10⁻³⁶) precipitate because ionic product $[Cu²⁺][S²⁻] = 0.01 × 10^{-21} = 10^{-23} > 10^{-36}$. Group IV sulfides (MnS Ksp ≈ 10⁻¹³) do NOT precipitate because $[Mn²⁺][S²⁻] = 0.01 × 10^{-21} = 10^{-23} < 10^{-13}$. In NH₃ (pH ≈ 9): $[S^{2-}] = 10^{-21}/(10^{-9})^2 = 10^{-3}$ M. Now: $[Mn²⁺][S²⁻] = 0.01 × 10^{-3} = 10^{-5} > 10^{-13}$ → MnS precipitates!
2. Why does lead appear in both Group I and Group II?
Pb²⁺ precipitates with both HCl (as PbCl₂, slightly soluble) and H₂S (as PbS, highly insoluble Ksp = 3×10⁻²⁸). If Pb²⁺ is present: it may not completely precipitate in Group I (PbCl₂ is only slightly insoluble compared to AgCl and Hg₂Cl₂). The incompletely precipitated Pb²⁺ then precipitates in Group II as black PbS. This is why Pb²⁺ is listed in both groups in some schemes. Confirmation: PbCl₂ dissolves in hot water (white crystals reform on cooling → characteristic). PbS is black. PbSO₄ is white (used to distinguish Pb²⁺ from Ba²⁺ in Group V — BaSO₄ also white, but PbSO₄ soluble in NaOH while BaSO₄ is not).
3. How does the confirmatory test for Fe³⁺ work?
KSCN test for Fe³⁺: $Fe^{3+} + SCN^- \to [Fe(SCN)]^{2+}$ (blood-red complex). Very sensitive — detects Fe³⁺ at ppm levels. The colour is due to charge transfer (CT) transition, not d-d transition → very intense colour. Not specific: Fe²⁺ does not give red colour with SCN⁻. Interfering ions: Cu²⁺ (but different colour), Co²⁺ (blue with SCN⁻ in acetone). Alternative test: K₄[Fe(CN)₆] (potassium hexacyanoferrate(II)): Fe³⁺ + K⁴[Fe(CN)₆] → KFe[Fe(CN)₆] = Prussian blue (intense blue precipitate). Very characteristic for Fe³⁺. K₃[Fe(CN)₆] tests for Fe²⁺: gives Turnbull's blue (also dark blue — actually same compound as Prussian blue, Turnbull's blue is a misnomer).
4. What is the Nessler reagent and what does it detect?
Nessler reagent: K₂[HgI₄] in alkaline solution (KOH). Detects NH₄⁺ ions. Reaction: NH₄⁺ + 2[HgI₄]²⁻ + 4OH⁻ → OHg₂NH₂I↓(brown/yellow) + 7I⁻ + 3H₂O. Small amounts: yellow colour. Larger amounts: brown precipitate. Very sensitive test for ammonium ion (and therefore ammonia). Used in water quality analysis to detect ammonium concentration. In qualitative analysis: test the original solution with Nessler reagent OR heat with NaOH — if NH₃ gas evolved (turns moist red litmus blue or forms white fumes with HCl) → NH₄⁺ present. Important: test for NH₄⁺ must be done before adding NaOH in systematic analysis (NaOH destroys NH₄⁺).
5. How are Group V cations (Ba²⁺, Sr²⁺, Ca²⁺) separated?
Group V precipitating reagent: ammonium carbonate (NH₄)₂CO₃ in ammoniacal solution (after removing Groups I-IV). All three precipitate as white carbonates: BaCO₃, SrCO₃, CaCO₃. To separate within Group V: dissolve precipitate in acetic acid. Add potassium chromate K₂CrO₄: BaCrO₄ (yellow) precipitates (Ksp 1.2×10⁻¹⁰) while SrCrO₄ and CaCrO₄ remain soluble (Ksp values higher). Confirm Ba²⁺: flame test (pale green). Separate Sr²⁺ from Ca²⁺: add dilute H₂SO₄ → SrSO₄ (Ksp 3.4×10⁻⁷) precipitates before CaSO₄ (Ksp 4.9×10⁻⁵). Confirm Sr²⁺: flame test (crimson red). Ca²⁺ remains in solution: oxalate test CaC₂O₄ (white precipitate in neutral/basic conditions). Confirm Ca²⁺: flame test (brick red).
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