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PhysicsFluid Mechanics / Oscillations

A cork floats on the surface of a liquid of density $\rho_2$. The density of cork is $\rho_1$. If the cork is pushed down and released, it undergoes SHM. The ratio $\rho_2/\rho_1$ at which the cork just sinks (fully submerged but in equilibrium at any depth) is:

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Solution written and verified by Roshan, science educator with 5 years of experience teaching NEET and JEE aspirants. Last reviewed September 2026.
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Correct Answer
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Solution
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Cork "just sinks" = neutral buoyancy = fully submerged, buoyant force = weight

$\rho_2 V g = \rho_1 V g \Rightarrow \rho_2 = \rho_1$

2

$\rho_2/\rho_1 = 1$

Answer: $\rho_2/\rho_1 = \mathbf{1}$

Neutral buoyancy: $\rho_{liquid} = \rho_{object}$ → ratio = 1
Float: $\rho_2 > \rho_1$; Sink: $\rho_2 < \rho_1$
Theory: Fluid Mechanics / Oscillations
1. Fluid Statics

Pressure in a fluid: $P = P_0 + \rho g h$ (Pascal\'s law). Pressure is same at same horizontal level. Manometer: measures gauge pressure ($P - P_{atm}$). Hydraulic press: $F_1/A_1 = F_2/A_2$ (same pressure transmitted). Buoyancy: $F_b = \rho_{fluid} V_{displaced} g$ (Archimedes). Object floats if $\rho_{obj} \leq \rho_{fluid}$.

2. Fluid Dynamics

Equation of continuity: $A_1 v_1 = A_2 v_2$ (mass conservation for incompressible fluid). Bernoulli\'s equation: $P + \frac{1}{2}\rho v^2 + \rho g h = $ const (energy conservation). Applications: airplane lift (Bernoulli + angle of attack), Venturi meter ($v_2 > v_1$ where $A_2 < A_1$, so $P_2 < P_1$), spray gun, Pitot tube (measures aircraft speed).

3. Viscosity and Surface Tension

Viscosity: $F = \eta A (dv/dy)$; $\eta$ = coefficient of viscosity (Pa s). Stokes law: drag on sphere = $6\pi\eta r v$; terminal velocity: $v_t = 2r^2(\rho-\rho_f)g/9\eta$. Surface tension: $T$ = force per unit length; pressure inside bubble: $\Delta P = 4T/r$ (soap bubble has 2 surfaces), $\Delta P = 2T/r$ (liquid drop, 1 surface). Capillary rise: $h = 2T\cos\theta/\rho g r$.

4. Elasticity

Stress = Force/Area. Strain = deformation/original dimension. Young\'s modulus: $Y = (F/A)/(l/L)$; stiffness for longitudinal deformation. Bulk modulus: $K = -V(dP/dV)$; resistance to volume change. Modulus of rigidity (shear modulus): $G = (F/A)/\theta$. Poisson\'s ratio: $\sigma = -(\Delta d/d)/(\Delta l/l)$. Energy stored in stretched wire: $U = \frac{1}{2}YAL\epsilon^2 = \frac{1}{2}\times stress \times strain \times volume$.

5. Bernoulli's Equation and Its Conditions

Bernoulli's equation, $P + \frac{1}{2}\rho v^2 + \rho gh = $ constant, is energy conservation per unit volume along a streamline. It assumes the flow is steady, incompressible, non-viscous and irrotational — conditions worth stating, because a question that mentions viscosity or turbulence is telling you Bernoulli does not apply. Where the speed is high the pressure is low, which explains aerofoil lift, the Venturi meter and why a shower curtain is pulled inward by the flowing water.

6. Terminal Velocity and Stokes' Law

A sphere falling through a viscous fluid experiences drag $F = 6\pi\eta rv$. It accelerates until drag plus buoyancy balances weight, after which it falls at constant terminal velocity $v_t = \frac{2r^2(\rho - \sigma)g}{9\eta}$. Note the $r^2$ dependence: doubling the radius quadruples the terminal speed, which is why fine dust stays suspended in air for hours while a pebble drops immediately.

7. Surface Tension and Excess Pressure

Surface tension arises because molecules at a liquid surface have unbalanced attractive forces pulling them inward, making the surface behave like a stretched membrane. The excess pressure inside a liquid drop is $2T/r$, but inside a soap bubble it is $4T/r$, because a bubble has two surfaces. Since excess pressure varies as 1/r, a small bubble has higher internal pressure than a large one — which is why, when two bubbles are connected, the smaller one empties into the larger.

Where students lose the mark

Applying Bernoulli across a viscous or turbulent flow. The equation assumes no energy is lost to friction. In a real pipe with viscosity, pressure drops along the length even at constant diameter.

Using $2T/r$ for a soap bubble. A bubble has an inner and an outer surface, so the excess pressure is $4T/r$. A drop has one surface and uses $2T/r$.

Frequently Asked Questions
1. What is the condition for floating? ⌄
Object floats when $\rho_{object} < \rho_{liquid}$. Fraction submerged = $\rho_{object}/\rho_{liquid}$. If $\rho_{object} = \rho_{liquid}$: neutral buoyancy (floats fully submerged). If $\rho_{object} > \rho_{liquid}$: sinks.
2. What is Archimedes principle? ⌄
Buoyant force = weight of displaced fluid = $ ho_{fluid} V_{submerged} g$. Acts upward through centre of buoyancy (centroid of displaced volume). Equilibrium: Buoyant force = Weight of object → $ ho_{fluid} V_{sub} g = ho_{object} V_{total} g$ → $V_{sub}/V_{total} = ho_{object}/ ho_{fluid}$.
3. Why does pushed cork undergo SHM? ⌄
When cork is pushed down by $x$: extra submerged volume = $A \cdot x$ (A = cross-section). Extra buoyant force = $\rho_{liquid} A x g$ (restoring force). $F = -\rho_{liquid} A g \cdot x$ (Hooke\'s law form). SHM with $\omega = \sqrt{\rho_{liquid} A g / m_{cork}} = \sqrt{\rho_{liquid} g / \rho_{cork} L}$ where $L$ = length.
4. What is the period of oscillating cork? ⌄
$\omega^2 = \rho_2 A g/m_1 = \rho_2 g/(\rho_1 L)$ where $L$ = length of cork. $T = 2\pi\sqrt{\rho_1 L/\rho_2 g}$. For cork fully submerged: no restoring force from buoyancy change → cannot oscillate in this simple way.
5. What are applications of buoyancy? ⌄
Ship design: steel ship floats because its average density (with air inside) < water. Submarine: ballast tanks filled with water to submerge, blown with air to surface. Hot air balloon: heated air less dense than cool surrounding air → buoyant force exceeds weight → rises. Density measurement by Archimedes method: $ ho = W_{air}/(W_{air}-W_{water}) imes ho_{water}$.
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