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ChemistryElectrochemistry
Which of the following statements about electrochemical cells are correct?
A. In a galvanic cell, the anode is negative and cathode is positive.
B. In an electrolytic cell, the anode is negative and cathode is positive.
C. The standard electrode potential of hydrogen electrode is taken as zero.
D. EMF of the cell = E°cathode − E°anode.
Options
1
A, C and D only
2
B, C and D only
3
A and C only
4
All A, B, C and D
Correct Answer
Option 1 : A, C and D only
Solution — Each Statement
A

Statement A — TRUE ✓

In a galvanic cell (spontaneous), oxidation occurs at the anode (releases electrons → negative electrode) and reduction at the cathode (gains electrons → positive electrode). External circuit: electrons flow from anode (−) to cathode (+).

B

Statement B — FALSE ✗

In an electrolytic cell, the anode is connected to the POSITIVE terminal of the battery, and the cathode to the NEGATIVE terminal. Anode = positive, cathode = negative. This is opposite to galvanic cell. Oxidation still at anode, reduction still at cathode — but the electrode signs are reversed.

C

Statement C — TRUE ✓

The Standard Hydrogen Electrode (SHE) is the universal reference with E° = 0.00 V by convention. All other standard electrode potentials are measured relative to SHE. Conditions: H₂ gas at 1 atm, H⁺ at 1 M concentration, 25°C.

D

Statement D — TRUE ✓

E°cell = E°cathode − E°anode (reduction potentials). This is the standard formula for cell EMF. Since cathode has higher reduction potential than anode for a spontaneous cell, E°cell is positive.

Theory: Electrochemistry
1. Galvanic vs Electrolytic Cell

📌 Galvanic cell: converts chemical energy → electrical energy (spontaneous)

📌 Electrolytic cell: converts electrical energy → chemical energy (non-spontaneous)

📌 Both: oxidation at anode, reduction at cathode

📌 Galvanic: anode(−), cathode(+) | Electrolytic: anode(+), cathode(−)

📌 Daniel cell: Zn|ZnSO₄||CuSO₄|Cu — classic galvanic cell

2. Standard Electrode Potential and EMF

E°cell = E°cathode − E°anode

ΔG° = −nFE°cell

E°cell = (RT/nF) ln K = (0.0591/n) log K at 25°C

A positive E°cell means the reaction is spontaneous (ΔG° < 0). The more positive E°cell, the more spontaneous. The standard hydrogen electrode (SHE) has E° = 0.00 V by definition — all other E° values are measured relative to it.

3. Nernst Equation

The Nernst equation relates cell EMF to concentration of reactants and products:

E = E° − (RT/nF) ln Q

E = E° − (0.0591/n) log Q (at 25°C)

At equilibrium: E = 0, Q = K → E° = (0.0591/n) log K

As reactants are consumed and products build up, Q increases and E decreases. When the cell reaches equilibrium (Q = K), E = 0 — the cell is dead (no more current flows). For concentration cells (same electrodes, different concentrations), E° = 0 but E ≠ 0.

4. Conductance — Kohlrausch's Law

Molar conductivity (Λm) increases with dilution — more dissociation means more ions available to carry charge. For strong electrolytes, Kohlrausch's law: Λm = Λ°m − K√c (Λm increases linearly with √c as concentration decreases). For weak electrolytes, molar conductivity increases steeply at low concentration as dissociation nears completion. Λ°m for weak electrolytes (e.g., acetic acid) cannot be measured directly — calculated using Kohlrausch's law of independent migration of ions: Λ°m(CH₃COOH) = Λ°m(HCl) + Λ°m(CH₃COONa) − Λ°m(NaCl).

5. Faraday's Laws of Electrolysis

First Law: m = ZIt = (M/nF) × Q

Second Law: m₁/m₂ = E₁/E₂ (equivalent weights)

1 Faraday = 96500 C = charge of 1 mol electrons

First law: mass deposited ∝ charge passed (Q = It). Second law: masses deposited by same charge are in ratio of their equivalent weights. Applications: electroplating, electrorefining of copper, chlor-alkali process (NaCl → Cl₂ + H₂ + NaOH), anodising aluminium.

6. Corrosion — Electrochemical Theory

Corrosion is the electrochemical degradation of metals. Iron rusting is an electrochemical process: Fe acts as anode (oxidised: Fe → Fe²⁺ + 2e⁻) and dissolved oxygen acts as cathode (reduced: O₂ + 2H₂O + 4e⁻ → 4OH⁻). The Fe²⁺ and OH⁻ combine to form Fe(OH)₂, which oxidises further to rust (Fe₂O₃·xH₂O). Prevention methods: painting, galvanising (Zn coating — sacrificial anode), cathodic protection (connecting iron to Mg or Zn), alloying (stainless steel — Cr forms protective Cr₂O₃ layer).

7. Batteries and Fuel Cells

📌 Daniel cell (primary): Zn-Cu, E° = 1.10 V

📌 Dry cell (Leclanché): Zn anode, MnO₂ cathode, NH₄Cl paste, ~1.5V

📌 Lead acid battery (secondary): Pb/PbSO₄|H₂SO₄|PbO₂/PbSO₄, 2V/cell, 6 cells=12V

📌 Nickel-cadmium: rechargeable, used in electronics

📌 Lithium-ion: high energy density, used in phones/EVs

📌 H₂-O₂ fuel cell: H₂ + ½O₂ → H₂O, only water as product, used in spacecraft

8. Electroplating

Electroplating deposits a thin layer of metal on another metal using electrolysis. The object to be plated is the cathode; the plating metal is the anode; electrolyte contains ions of the plating metal. Applications: silver plating cutlery, gold plating jewellery, chrome plating car parts, tin plating food cans (prevents corrosion), nickel plating for hardness. The thickness of deposit depends on current density and time (Faraday's first law).

Frequently Asked Questions
1. Why is anode negative in galvanic but positive in electrolytic cell?
In galvanic cell, oxidation at anode releases electrons — excess electrons make anode negative (like a battery negative terminal). In electrolytic cell, the external battery forces current in — the positive terminal of battery is connected to anode, making it positive. Reaction at anode is always oxidation, but the sign depends on whether the cell is spontaneous or forced.
2. What is the standard electrode potential of Zn?
E°(Zn²⁺/Zn) = −0.76 V (vs SHE). Negative means Zn is a better reducing agent than H₂ — Zn can displace H₂ from dilute acids. For Daniel cell: E°cell = E°Cu − E°Zn = +0.34 − (−0.76) = +1.10 V. Positive E°cell → spontaneous reaction → Zn is oxidised, Cu²⁺ is reduced.
3. What is the Nernst equation for Daniel cell?
Zn + Cu²⁺ → Zn²⁺ + Cu. E = E° − (0.0591/2) log([Zn²⁺]/[Cu²⁺]). If [Zn²⁺] = [Cu²⁺] = 1M: E = 1.10 V. If [Cu²⁺] increases (higher): E increases (log term decreases). At equilibrium: E = 0, log K = 2×1.10/0.0591 = 37.2, K = 10^37.2 (huge — reaction goes essentially to completion).
4. What is 1 Faraday?
1 Faraday (F) = 96500 C/mol = charge carried by 1 mole of electrons. It's named after Michael Faraday. To deposit 1 mole of a monovalent metal (like Ag): requires 1 F = 96500 C. For divalent metal (like Cu): requires 2 F = 193000 C (2 electrons per Cu²⁺ ion). Electrolysis of water: 2 F required to produce 1 mol H₂ and ½ mol O₂.
5. How does a lead-acid battery work?
Discharge (galvanic): Pb (anode) → Pb²⁺ → PbSO₄. PbO₂ (cathode) + H⁺ → PbSO₄. H₂SO₄ is consumed, density decreases. Charge (electrolytic): PbSO₄ → Pb (cathode) and PbO₂ (anode). H₂SO₄ regenerated. Each cell = 2V; 6 cells in series = 12V car battery. Specific gravity of H₂SO₄ indicates state of charge.
6. What is Kohlrausch's law and its application?
Kohlrausch's law of independent ion migration: at infinite dilution, each ion contributes independently to molar conductivity. Λ°m(electrolyte) = λ°+(cation) + λ°−(anion). Used to find Λ°m of weak electrolytes indirectly: Λ°m(CH₃COOH) = λ°H⁺ + λ°CH₃COO⁻. From Λ°m and measured Λm, degree of dissociation α = Λm/Λ°m, then Ka = cα²/(1−α).
7. How does galvanising prevent corrosion?
Galvanising coats iron with zinc. Zinc has more negative E° (−0.76V) than iron (−0.44V) — Zn is more easily oxidised. So Zn acts as sacrificial anode — even if the zinc coating is scratched exposing iron, the Zn around it still corrodes preferentially, protecting the iron. Tin plating (used in food cans) works differently — if scratched, iron corrodes faster (Fe is more easily oxidised than Sn).
8. What is the relation between E°cell, ΔG° and K?
ΔG° = −nFE°cell = −RT ln K. These three quantities all measure the same thing — the spontaneity and extent of reaction. E°cell > 0 ↔ ΔG° < 0 ↔ K > 1 (products favoured). At 25°C: E°cell = (0.0591/n) log K. Each 0.0591/n volt corresponds to a factor of 10 in K.
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