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PhysicsUnits & Measurements
Each side of a metallic cube of mass 5·580 kg is measured to be 9·0 cm. Keeping the significant figures in view, the density of the material of the cube can be best expressed as X × 10³ kg m⁻³, where the value of X is :
Options
1
7·654
2
7·7
3
7·65
4
7·6
Correct Answer
Option 2 : X = 7·7
Step-by-Step Solution
1

Count significant figures in given data:

Mass m = 5·580 kg → 4 significant figures (trailing zero after decimal is significant)

Side a = 9·0 cm = 9·0 × 10⁻² m → 2 significant figures

2

Calculate density:

V = a³ = (9·0 × 10⁻²)³ = 729 × 10⁻⁶ m³

ρ = m/V = 5·580 / (729 × 10⁻⁶) = 7654·3... kg/m³ = 7·6543 × 10³ kg/m³

3

Apply significant figures rule for division:

In multiplication/division: result has same sig figs as the least precise measurement.

Least sig figs = 2 (from side = 9·0 cm)

Round 7·6543 to 2 significant figures → 7·7

∴ ρ = 7·7 × 10³ kg/m³ → X = 7·7

ρ = m/a³ = 5.580/(729×10⁻⁶) = 7654 kg/m³

Rounded to 2 sig figs (from a = 9.0 cm) = 7.7 × 10³ kg/m³

Theory: Significant Figures & Error Analysis
1. Rules for Counting Significant Figures

📌 All non-zero digits are significant: 1234 → 4 sig figs

📌 Zeros between non-zero digits are significant: 1002 → 4 sig figs

📌 Leading zeros (before first non-zero digit) are NOT significant: 0·0012 → 2 sig figs

📌 Trailing zeros AFTER decimal point ARE significant: 9·0 → 2 sig figs; 5·580 → 4 sig figs

📌 Trailing zeros WITHOUT decimal point are ambiguous: 1200 could be 2, 3, or 4 sig figs

📌 Use scientific notation to be unambiguous: 1·2 × 10³ (2 sig figs); 1·200 × 10³ (4 sig figs)

2. Rules for Arithmetic Operations

The key principle: the result cannot be more precise than the least precise measurement used. For addition and subtraction: retain as many decimal places as the measurement with the fewest decimal places. Example: 3·125 + 1·7 = 4·825 → round to 4·8 (1 decimal place, same as 1·7). For multiplication and division: retain as many significant figures as the measurement with the fewest significant figures. Example: 2·5 × 3·14 = 7·85 → round to 7·9 (2 sig figs, same as 2·5).

3. Why 9·0 Has Only 2 Sig Figs (Not 1)?

Writing 9·0 (with decimal point and trailing zero) explicitly indicates the measurement was made to the nearest 0·1 cm — the zero is significant. If we wrote just "9", it would mean we only know the measurement to the nearest 1 cm (1 significant figure). By writing 9·0, the experimenter signals: "I measured this to be 9·0 cm, not 8·9 or 9·1." This distinction is crucial in scientific reporting. Similarly, 5·580 (not 5·58) tells us the fourth digit is 0, not unknown.

4. Types of Errors in Measurements

📌 Systematic error: Same direction every time — instrument calibration error, zero error, personal bias. Can be corrected if identified.

📌 Random error: Unpredictable fluctuations — reduced by taking multiple measurements and averaging.

📌 Gross error: Blunders — reading instrument wrongly, noting wrong value. Eliminated by careful observation.

📌 Least count error: Due to finite precision of instrument. Cannot be smaller than the least count of the measuring instrument.

5. Absolute, Relative, and Percentage Error

Absolute error: Δa = |a_measured − a_true|. Mean absolute error: Δa_mean = (Δa₁ + Δa₂ + ... + Δaₙ)/n. Relative error: Δa/a (dimensionless). Percentage error: (Δa/a) × 100%. For derived quantities using multiplication/division: the relative errors add. Example: ρ = m/V = m/a³. Then Δρ/ρ = Δm/m + 3(Δa/a). The factor 3 comes from the power 3 on 'a' — errors in a get multiplied 3 times. This shows why accurately measuring linear dimensions is critical for volume calculations.

6. Propagation of Errors in Formulae

📌 Addition/Subtraction: Z = A ± B → ΔZ = ΔA + ΔB (absolute errors add)

📌 Multiplication/Division: Z = A×B or A/B → ΔZ/Z = ΔA/A + ΔB/B (relative errors add)

📌 Power: Z = Aⁿ → ΔZ/Z = n(ΔA/A) (relative error multiplied by power)

📌 Example: T = 2π√(L/g) → ΔT/T = ½(ΔL/L) + ½(Δg/g)

📌 Note: errors always ADD (never cancel) — worst-case analysis

7. Dimensions and Dimensional Analysis

Every physical quantity has dimensions expressed in terms of fundamental quantities: M (mass), L (length), T (time), A (current), K (temperature), mol (amount), cd (luminous intensity). Uses of dimensional analysis: (1) Check correctness of equations — dimensions must match on both sides. (2) Derive formulae — if you know which quantities are involved and how they relate dimensionally. (3) Convert units between systems. Limitations: dimensionless constants cannot be determined; cannot distinguish between scalar and vector quantities; doesn't work for trigonometric or logarithmic functions.

8. Accuracy vs Precision

Accuracy refers to how close a measurement is to the true value — it relates to systematic error. Precision refers to how reproducible measurements are — it relates to random error. A measurement can be precise but inaccurate (e.g., consistently reading 2 cm too high due to a calibration error). A measurement can be accurate on average but imprecise (large scatter around the true value). Good experimental design aims for both: well-calibrated instruments (accuracy) AND multiple measurements with averaging (precision).

Frequently Asked Questions
1. Why is the answer 7·7 and not 7·654 or 7·65?
The rule: in multiplication/division, round the result to have the same number of significant figures as the least precise measurement. Here, a = 9·0 cm has only 2 sig figs (the least). Mass = 5·580 kg has 4 sig figs. So the result ρ = 7·6543... × 10³ must be rounded to 2 sig figs → 7·7 × 10³. Options 7·654 (4 sig figs) and 7·65 (3 sig figs) retain too many significant figures.
2. How many significant figures does 5·580 have?
5·580 has 4 significant figures. The trailing zero after the decimal point is significant — it tells us the measurement was made to 4 significant figures (thousandths of a kg). If it were 5·58, that would be 3 significant figures. The explicit trailing zero in 5·580 is meaningful and must be counted.
3. What is the volume of the cube in SI units?
Side a = 9·0 cm = 9·0 × 10⁻² m = 0·090 m. V = a³ = (9·0 × 10⁻²)³ = (9·0)³ × (10⁻²)³ = 729 × 10⁻⁶ m³ = 7·29 × 10⁻⁴ m³. Note: (9·0)³ = 9·0 × 9·0 × 9·0 = 81·0 × 9·0 = 729. Always convert to SI units first to avoid unit conversion errors.
4. What is the significance of expressing density as X × 10³?
Scientific notation (X × 10ⁿ) makes comparing magnitudes easy and unambiguously shows significant figures. Density of metals is typically 10³−10⁴ kg/m³. X = 7·7 means density ≈ 7700 kg/m³, which is close to steel (~7874 kg/m³) or iron (~7874 kg/m³). This helps identify the material. Water = 1000 kg/m³ (X = 1), aluminium ≈ 2700 (X = 2·7), gold ≈ 19,300 (X = 19·3).
5. In error propagation, why do errors add and not subtract?
We always consider the worst-case (maximum possible) error. Errors in different quantities can compound in the worst case — even if they partially cancel in one measurement, we cannot count on that. So we always add absolute errors (never subtract). This gives an upper bound on the total error, ensuring our stated error range definitely contains the true value.
6. How does the error in side affect the error in volume?
V = a³. Using error propagation: ΔV/V = 3(Δa/a). If Δa/a = 1% (1% error in side measurement), then ΔV/V = 3%. The cube relationship amplifies the error 3-fold. This shows why side measurement is critical — a small error in measuring the side causes a 3× larger percentage error in the volume, which then affects the density calculation.
7. What is the difference between accuracy and precision with an example?
Imagine measuring a 10 cm rod: Accurate and precise: 10·01, 9·99, 10·00, 10·02 cm (close to 10, small scatter). Precise but not accurate: 8·99, 9·00, 9·01, 9·00 cm (consistent but all ~9 cm, systematic error). Accurate but not precise: 9·5, 10·3, 10·0, 9·8 cm (average ≈ 10 cm but large scatter). Neither: 8·5, 11·2, 9·1, 10·8 cm (neither close to 10 nor consistent).
8. Why can't we trust more decimal places than our least count?
A ruler with 1 mm least count cannot measure to 0·1 mm — the extra digit would be fabricated. Reporting 9·05 cm from a ruler with 1 mm divisions is scientifically dishonest. The least count defines the limit of precision. We can interpolate between divisions (estimate one extra digit), but no more. A Vernier caliper (LC = 0·01 cm) can legitimately give 9·05 cm. The choice of instrument determines how many significant figures are meaningful.
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