NeetCrackers Chemistry Practice
Practice Set

Solutions — Practice Questions with Answers

30 fully solved questions covering concentration terms, Raoult's law, colligative properties, and van't Hoff factor.

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Questions written and solutions verified by Roshan, science educator with 5 years of experience teaching NEET and JEE aspirants. Checked against NCERT and previous years' papers. Last reviewed September 2026.
10MCQs · 1 mark
10Short Answer · 3 marks
10Long Answer · 5 marks
90Total Marks

📑 On This Page

  1. Section A — 10 MCQs (1 mark each)
  2. Section B — 10 Short Answer Questions (3 marks each)
  3. Section C — 10 Long Answer Questions (5 marks each)
Section A

🎯 Multiple Choice Questions

10 questions · 1 mark each · Correct answer highlighted with explanation

Q1 According to Raoult's law, the vapour pressure of a solution containing a non-volatile solute is:
Correct Answer: (b). Adding a non-volatile solute lowers the solvent's vapour pressure, since fewer solvent molecules occupy the surface, reducing evaporation rate.
Q2 Colligative properties of a solution depend on:
Correct Answer: (b). Colligative properties depend purely on the concentration (number) of dissolved solute particles, regardless of their specific chemical identity.
Q3 Which of the following is NOT a colligative property?
Correct Answer: (c). Colour depends on the specific chemical identity of the solute, not merely its particle count — it is not a colligative property.
Q4 The van't Hoff factor ($i$) for a solute that dissociates into $n$ ions (complete dissociation) is:
Correct Answer: (b) $n$. Complete dissociation into $n$ ions gives $i=n$ (e.g., NaCl fully dissociating gives $i=2$).
Q5 Osmosis refers to the movement of solvent molecules through a semi-permeable membrane from:
Correct Answer: (a). Solvent naturally moves towards the region of higher solute concentration (lower solvent concentration), to equalise concentration across the membrane.
Q6 A solution that obeys Raoult's law over the entire range of concentration is called:
Correct Answer: (a). An ideal solution follows Raoult's law across its entire concentration range, typically formed by components with very similar intermolecular forces.
Q7 The molal depression constant ($K_f$) is defined as the depression in freezing point when the molality of the solution is:
Correct Answer: (a). $K_f$ is a solvent-specific constant, representing the freezing point depression for a hypothetical 1 molal solution.
Q8 Reverse osmosis is used practically for:
Correct Answer: (a). Reverse osmosis applies external pressure exceeding osmotic pressure, forcing pure solvent (water) through a membrane, widely used for water purification/desalination.
Q9 A negative deviation from Raoult's law occurs when:
Correct Answer: (a). Stronger solute-solvent (unlike molecule) attractions than like-molecule attractions reduce escaping tendency, lowering vapour pressure below the Raoult's law prediction (negative deviation).
Q10 The van't Hoff factor for a solute that associates (e.g., dimerises) in solution is:
Correct Answer: (b). Association reduces the effective number of independent particles in solution, giving a van't Hoff factor less than 1 (e.g., $i \approx 0.5$ for complete dimerisation).
Section B

✍️ Short Answer Questions

10 questions · 3 marks each · Full model answers included

Q1. State Raoult's law for a solution containing a non-volatile solute.
3 Marks
Answer

Raoult's law states that the vapour pressure of a solvent above a solution is directly proportional to its mole fraction in the solution: $P_{solution} = x_{solvent}\times P^0_{solvent}$, where $P^0_{solvent}$ is the vapour pressure of the pure solvent.

Since adding a non-volatile solute reduces the solvent's mole fraction (which must be less than 1), the solution's vapour pressure is correspondingly lower than that of the pure solvent.

Q2. Define colligative properties, and list the four main colligative properties studied.
3 Marks
Answer

Colligative properties are properties of a solution that depend only on the number (concentration) of solute particles present, not on their specific chemical identity or nature.

The four main colligative properties are: (1) relative lowering of vapour pressure, (2) elevation of boiling point, (3) depression of freezing point, and (4) osmotic pressure.

Q3. Explain why the boiling point of a solution containing a non-volatile solute is higher than that of the pure solvent.
3 Marks
Answer

Adding a non-volatile solute lowers the solvent's vapour pressure at any given temperature (per Raoult's law). Since boiling occurs when vapour pressure equals atmospheric pressure, this lowered vapour pressure means the solution must be heated to a higher temperature than the pure solvent for its vapour pressure to reach atmospheric pressure — this is precisely why boiling point elevation occurs for solutions containing non-volatile solutes.

Q4. Define osmotic pressure, and write the van't Hoff equation relating osmotic pressure to concentration and temperature.
3 Marks
Answer

Osmotic pressure is the minimum external pressure that must be applied to a solution to just prevent the net inward flow of solvent molecules through a semi-permeable membrane separating it from pure solvent (i.e., to stop osmosis).

Van't Hoff equation: $\pi = CRT$, where $\pi$ is osmotic pressure, $C$ is molar concentration, $R$ is the gas constant, and $T$ is absolute temperature — analogous in form to the ideal gas equation.

Q5. What is meant by the van't Hoff factor? Explain how it accounts for the effects of dissociation and association of solutes on colligative properties.
3 Marks
Answer

The van't Hoff factor ($i$) is the ratio of the actual (experimentally observed) colligative property value to the theoretically calculated value assuming no dissociation or association of the solute — $i = \dfrac{\text{observed value}}{\text{calculated value (no dissociation/association)}}$.

For solutes that dissociate (e.g., ionic compounds splitting into ions), $i > 1$, since more actual particles are present than the simple formula unit count would suggest. For solutes that associate (e.g., molecules pairing up), $i < 1$, since fewer independent particles are effectively present than the simple molecular count would suggest.

Q6. Distinguish between an ideal solution and a non-ideal solution.
3 Marks
Answer

An ideal solution obeys Raoult's law across the entire concentration range, typically because the solute-solvent intermolecular interactions are essentially similar in strength to the solute-solute and solvent-solvent interactions — no significant enthalpy or volume change occurs on mixing.

A non-ideal solution deviates from Raoult's law (either positively or negatively), because solute-solvent interactions differ significantly (either weaker or stronger) from solute-solute and solvent-solvent interactions — typically accompanied by a non-zero enthalpy and/or volume change on mixing.

Q7. Explain why NaCl has a van't Hoff factor close to 2 in dilute aqueous solution.
3 Marks
Answer

NaCl is an ionic compound that, upon dissolving in water, dissociates essentially completely into its constituent ions: $NaCl \rightarrow Na^+ + Cl^-$.

Since each formula unit of NaCl produces two independent particles (one $Na^+$ ion and one $Cl^-$ ion) in solution, the effective particle concentration is approximately double what the simple formula unit concentration would suggest — this is precisely why the van't Hoff factor for NaCl in dilute solution is close to 2, reflecting this near-complete dissociation into two ions per formula unit.

Q8. What is meant by "isotonic solutions"? Why is this concept medically important, particularly for intravenous fluids?
3 Marks
Answer

Isotonic solutions are two solutions that have the same osmotic pressure as each other — when separated by a semi-permeable membrane, no net movement of solvent occurs between them.

Medical importance: Intravenous fluids administered to patients must be isotonic with blood plasma/cells — if a fluid were hypotonic (lower osmotic pressure than cells), water would flow into cells, potentially causing them to swell and burst; if hypertonic (higher osmotic pressure), water would flow out of cells, causing them to shrink (crenate) — both outcomes can cause serious cellular damage, which is precisely why isotonic solutions are essential for safe intravenous fluid administration.

Q9. Explain why colligative property measurements can be used to determine the molar mass of an unknown solute.
3 Marks
Answer

Colligative properties (like freezing point depression or boiling point elevation) are directly related to the molar concentration (and hence the number of moles) of solute present, via known constants ($K_f$ or $K_b$) specific to the solvent used.

By experimentally measuring a colligative property change for a solution prepared with a known mass of solute in a known mass/volume of solvent, the number of moles of solute present can be calculated (using the appropriate colligative property equation) — since moles = mass/molar mass, and both mass and moles are now known, the unknown molar mass of the solute can be readily determined by rearranging this relationship.

Q10. Explain the phenomenon of positive deviation from Raoult's law, with an example.
3 Marks
Answer

Positive deviation occurs when solute-solvent interactions are weaker than the solute-solute and solvent-solvent interactions present in the pure components — this weaker mutual attraction increases the escaping tendency of both components, resulting in a higher observed vapour pressure than Raoult's law would predict.

Example: A mixture of ethanol and acetone shows positive deviation, since the ethanol-acetone interactions (via disrupted hydrogen bonding compared to pure ethanol) are weaker than the interactions present in the pure components alone, resulting in greater-than-expected vapour pressure for the mixture.

Section C

📘 Long Answer / Numerical Questions

10 questions · 5 marks each · Detailed step-by-step solutions

Q1. Calculate the relative lowering of vapour pressure of a solution containing 18 g of glucose (molar mass 180 g/mol) dissolved in 90 g of water (molar mass 18 g/mol).
5 Marks
Answer

Moles of glucose (solute) $= 18/180 = 0.1\text{ mol}$; Moles of water (solvent) $= 90/18 = 5\text{ mol}$

Mole fraction of solute: $x_{solute} = \dfrac{0.1}{0.1+5} = \dfrac{0.1}{5.1} \approx 0.0196$

Relative lowering of vapour pressure $= x_{solute}$ (by Raoult's law, for dilute solutions)

Relative lowering $\approx \mathbf{0.0196}$ (or 1.96%)

Q2. Find the freezing point depression of a solution containing 6 g of urea (molar mass 60 g/mol) dissolved in 200 g of water ($K_f$ for water = 1.86 K·kg/mol).
5 Marks
Answer

Molality $= \dfrac{\text{moles of solute}}{\text{mass of solvent in kg}} = \dfrac{6/60}{0.2} = \dfrac{0.1}{0.2} = 0.5\text{ mol/kg}$

$\Delta T_f = K_f\times m = 1.86\times0.5$

$\Delta T_f = \mathbf{0.93\text{ K}}$

Q3. Calculate the osmotic pressure of a solution prepared by dissolving 34.2 g of sucrose (molar mass 342 g/mol) in enough water to make 1 L of solution, at 300 K (R = 0.0821 L·atm/mol·K).
5 Marks
Answer

Moles of sucrose $= 34.2/342 = 0.1\text{ mol}$

Molar concentration $C = \dfrac{0.1\text{ mol}}{1\text{ L}} = 0.1\text{ mol/L}$

$\pi = CRT = 0.1\times0.0821\times300$

$\pi = \mathbf{2.463\text{ atm}}$

Q4. A solution contains 0.1 mol of NaCl in 1 kg of water, and shows an observed freezing point depression of 0.348 K. Given $K_f=1.86$ K·kg/mol, calculate the van't Hoff factor for NaCl in this solution.
5 Marks
Answer

Molality $m = 0.1\text{ mol/kg}$ (since 0.1 mol dissolved in 1 kg water)

Theoretical (calculated, no dissociation) $\Delta T_f = K_f\times m = 1.86\times0.1 = 0.186\text{ K}$

Van't Hoff factor: $i = \dfrac{\text{observed }\Delta T_f}{\text{calculated }\Delta T_f} = \dfrac{0.348}{0.186}$

$i \approx \mathbf{1.87}$ (close to the ideal value of 2 for complete dissociation into $Na^+$ and $Cl^-$, with some deviation due to ionic interactions in real solution)

Q5. Find the boiling point elevation of a solution containing 12 g of a non-volatile, non-electrolyte solute (molar mass 60 g/mol) dissolved in 200 g of water ($K_b$ for water = 0.52 K·kg/mol).
5 Marks
Answer

Molality $= \dfrac{12/60}{0.2} = \dfrac{0.2}{0.2} = 1\text{ mol/kg}$

$\Delta T_b = K_b\times m = 0.52\times1$

$\Delta T_b = \mathbf{0.52\text{ K}}$

Q6. A 0.5 molal aqueous solution of a weak electrolyte shows a freezing point depression of 1.033 K. Given $K_f=1.86$ K·kg/mol, calculate the van't Hoff factor and degree of dissociation, assuming the electrolyte dissociates into 2 ions.
5 Marks
Answer

Calculated (undissociated) $\Delta T_f = K_f\times m = 1.86\times0.5 = 0.93\text{ K}$

Van't Hoff factor: $i = \dfrac{1.033}{0.93} \approx 1.111$

For dissociation into $n=2$ ions with degree of dissociation $\alpha$: $i = 1+\alpha(n-1) = 1+\alpha$

$1.111 = 1+\alpha \Rightarrow \alpha = 0.111$

Degree of dissociation $\alpha \approx 0.111$ (11.1%)

Q7. Calculate the molar mass of a non-volatile solute if 2.5 g of it, dissolved in 100 g of water, produces a freezing point depression of 0.372 K ($K_f=1.86$ K·kg/mol).
5 Marks
Answer

Molality: $\Delta T_f = K_f\times m \Rightarrow m = \dfrac{\Delta T_f}{K_f} = \dfrac{0.372}{1.86} = 0.2\text{ mol/kg}$

Moles of solute $= m\times(\text{mass of solvent in kg}) = 0.2\times0.1 = 0.02\text{ mol}$

Molar mass $= \dfrac{\text{mass}}{\text{moles}} = \dfrac{2.5}{0.02}$

Molar mass $= \mathbf{125\text{ g/mol}}$

Q8. Two solutions of glucose have concentrations 0.1 M and 0.2 M at the same temperature. Find the ratio of their osmotic pressures.
5 Marks
Answer

Since $\pi = CRT$, at the same temperature, $\pi \propto C$

$\dfrac{\pi_1}{\pi_2} = \dfrac{C_1}{C_2} = \dfrac{0.1}{0.2} = \mathbf{\dfrac{1}{2}}$

The solution with 0.2 M concentration has twice the osmotic pressure of the 0.1 M solution.

Q9. Calculate the mole fraction of solute and solvent in a solution containing 5 moles of solute and 45 moles of solvent, and find the relative lowering of vapour pressure.
5 Marks
Answer

Total moles $= 5+45=50$

Mole fraction of solute: $x_{solute} = 5/50 = 0.1$

Mole fraction of solvent: $x_{solvent} = 45/50 = 0.9$

Relative lowering of vapour pressure $= x_{solute} = \mathbf{0.1}$ (10%)

Q10. Find the osmotic pressure at 300 K of a 0.01 M solution of $K_2SO_4$, assuming complete dissociation (van't Hoff factor $i=3$, since $K_2SO_4 \rightarrow 2K^++SO_4^{2-}$). (R = 0.0821 L·atm/mol·K)
5 Marks
Answer

For an electrolyte solution, the van't Hoff equation is modified: $\pi = iCRT$

$\pi = 3\times0.01\times0.0821\times300$

$\pi = 3\times0.2463$

$\pi = \mathbf{0.7389\text{ atm}}$

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