HomeChemistryQ
ChemistryHaloalkanes & Haloarenes
The number of chlorine atoms present in the organic products X and Y of the following reactions, respectively, are :
C₆H₆ + 6Cl₂ →(Anhydr. AlCl₃, dark, cold) X
C₆H₆ + 3Cl₂ →(UV, 500 K) Y
Options
1
3 and 6
2
6 and 6
3
6 and 3
4
3 and 3
Correct Answer
Option 2 : 6 and 6
Step-by-Step Solution
1

Reaction 1 — Electrophilic Aromatic Substitution (EAS):

C₆H₆ + 6Cl₂ →(Anhydrous AlCl₃, dark, cold) X

AlCl₃ is a Lewis acid catalyst. All 6 H atoms of benzene are replaced by Cl one by one.

Product X = Hexachlorobenzene (C₆Cl₆) — 6 Cl atoms on the ring

C₆H₆ + 6Cl₂ → C₆Cl₆ + 6HCl

2

Reaction 2 — Free Radical Addition:

C₆H₆ + 3Cl₂ →(UV light, 500 K) Y

UV light initiates free radical mechanism. Cl₂ adds across the double bonds of benzene ring.

Product Y = Benzene hexachloride / BHC (C₆H₆Cl₆) = Lindane (γ-BHC) — 6 Cl atoms added

C₆H₆ + 3Cl₂ → C₆H₆Cl₆

X = C₆Cl₆ (Hexachlorobenzene) → 6 Cl atoms (substitution)
Y = C₆H₆Cl₆ (BHC/Lindane) → 6 Cl atoms (addition)
Answer: 6 and 6
Theory: Reactions of Benzene
1. Electrophilic Aromatic Substitution (EAS) — Key Concept

Benzene's π electron cloud acts as a nucleophile toward electrophiles. Unlike alkenes, benzene undergoes substitution (not addition) to maintain aromaticity — because aromaticity provides exceptional stability. The general mechanism: (1) Electrophile (E⁺) attacks benzene → arenium ion (σ-complex/Wheland intermediate — loses aromaticity temporarily). (2) Loss of H⁺ restores aromaticity → substituted product. In this case: AlCl₃ activates Cl₂ → Cl⁺ (electrophile). Cl⁺ substitutes each H on benzene progressively until all 6 H atoms are replaced → hexachlorobenzene.

2. Free Radical Addition to Benzene — BHC Formation

Under UV light, Cl₂ undergoes homolytic cleavage → Cl• radicals. These radicals add across the double bonds of benzene (which temporarily loses its aromaticity). Three moles of Cl₂ add to one mole of benzene (across 3 double bonds): C₆H₆ + 3Cl₂ → C₆H₆Cl₆. The product BHC (Benzene HexaChloride) has 6 C atoms, 6 H atoms, and 6 Cl atoms — formula C₆H₆Cl₆. γ-isomer (lindane) was used as a pesticide/insecticide (now banned in many countries due to toxicity and persistence).

3. Key Difference: EAS vs Free Radical Addition

📌 EAS (AlCl₃, dark): Substitution — H replaced by Cl. Aromaticity maintained. Product: C₆Cl₆ (all H replaced). 6 Cl atoms in ring position.

📌 Free Radical Addition (UV/heat): Addition — Cl adds to double bonds. Aromaticity lost. Product: C₆H₆Cl₆ (H atoms retained, Cl added). 6 Cl atoms added to ring carbons.

📌 Both products have 6 Cl atoms — but for completely different reasons!

📌 EAS: catalyst needed (Lewis acid) — no UV. Addition: UV or high temperature needed — no catalyst.

4. Other EAS Reactions of Benzene

📌 Nitration: C₆H₆ + HNO₃ →(conc. H₂SO₄) C₆H₅NO₂ (nitrobenzene)

📌 Sulphonation: C₆H₆ + H₂SO₄ →(fuming H₂SO₄) C₆H₅SO₃H (benzenesulphonic acid) — reversible!

📌 Halogenation: C₆H₆ + Cl₂ →(AlCl₃) C₆H₅Cl (chlorobenzene) + HCl

📌 Friedel-Crafts alkylation: C₆H₆ + RCl →(AlCl₃) C₆H₅R (alkylbenzene)

📌 Friedel-Crafts acylation: C₆H₆ + RCOCl →(AlCl₃) C₆H₅COR (aryl ketone)

5. Activating and Deactivating Groups in EAS

Substituents already on benzene ring direct incoming electrophile to ortho/para or meta positions and either activate (increase reactivity) or deactivate (decrease reactivity) the ring. Ortho/para directors (activating): −NH₂, −OH, −OCH₃, −NHCOCH₃, −alkyl. These donate electrons to ring via resonance or induction. Ortho/para directors (deactivating): −X (halogens) — withdraw by induction but donate by resonance (net deactivating). Meta directors (deactivating): −NO₂, −CN, −COOH, −CHO, −SO₃H, −COOR. These withdraw electrons from ring, making meta position relatively less deactivated.

6. Structure and Aromaticity of Benzene

Benzene (C₆H₆) is a flat, regular hexagon. All C–C bond lengths are equal (1·40 Å — between single 1·54 Å and double 1·34 Å). All bond angles = 120°. The 6 π electrons are fully delocalised over the ring — one electron per carbon in p-orbital, all perpendicular to ring plane. Hückel's rule: aromaticity requires (4n+2) π electrons (n = 0, 1, 2...). For benzene: 6 = 4(1)+2 → n=1 ✓. Resonance energy = ~150 kJ/mol — this is why benzene prefers substitution over addition (to retain aromaticity and this stabilisation).

7. DDT and Organochlorine Pesticides

DDT (dichlorodiphenyltrichloroethane) and BHC (lindane) are organochlorine pesticides. They were widely used in agriculture and malaria control (DDT kills Anopheles mosquitoes). Problems: extremely persistent in environment (don't biodegrade easily), accumulate in food chains (biomagnification) — higher concentrations at each trophic level. Found in human fat tissue, breast milk. DDT banned in most countries (Stockholm Convention, 2004). Still used in some tropical countries for malaria vector control — no alternatives are as cheap/effective. Environmental impact: caused decline of birds of prey (thinning of eggshells).

8. Nucleophilic Aromatic Substitution (NAS)

Unlike aliphatic halides, aryl halides (C₆H₅Cl) are very resistant to nucleophilic substitution because: (1) Cl is attached to sp² carbon (stronger C–Cl bond). (2) Cl lone pairs are delocalised into ring (partial double bond character). (3) Nucleophile approach is blocked by ring π electrons. NAS occurs only when strong electron-withdrawing groups (−NO₂) are present ortho/para to the leaving group — they stabilise the negative intermediate (Meisenheimer complex). Example: 2,4-dinitrochlorobenzene + NaOH → 2,4-dinitrophenol (NAS).

Frequently Asked Questions
1. Why does Reaction 1 give substitution but Reaction 2 gives addition?
Reaction 1 (AlCl₃, dark): Lewis acid AlCl₃ generates Cl⁺ electrophile. This attacks the π electrons of benzene via EAS mechanism. After substitution, aromaticity is restored — which is thermodynamically very stable. Substitution is favoured. Reaction 2 (UV light): UV photons cause homolytic cleavage of Cl₂ → Cl• radicals. Free radicals follow a different (radical addition) mechanism. Aromaticity is temporarily lost during addition, but since no acid catalyst is present to trigger substitution, the radical pathway leads to addition product (BHC).
2. What is BHC and what are its uses?
BHC = Benzene HexaChloride = C₆H₆Cl₆. Also called hexachlorocyclohexane (HCH). Has 8 stereoisomers (α, β, γ, δ, ε, ζ, η, θ). γ-isomer (γ-BHC) = Lindane = most insecticidal isomer. Was used as: agricultural pesticide (against aphids, lice), treatment of scabies and lice on humans, soil insecticide. Now banned in most countries due to neurotoxicity, persistence, bioaccumulation. Still used in some countries for head lice treatment. NEET often asks: "which gamma isomer of BHC is used as insecticide?" Answer: Lindane.
3. Why does benzene prefer substitution over addition?
Benzene has a resonance energy of ~150 kJ/mol — this extra stability from delocalisation of 6 π electrons is "aromaticity." Addition reactions would disrupt this delocalisation, converting benzene to a cyclohexadiene (non-aromatic) — losing the ~150 kJ/mol stabilisation. Substitution restores aromaticity after the reaction. So thermodynamically, substitution is strongly preferred. Only under forcing conditions (radical mechanism with UV) does addition occur, because radicals bypass the thermodynamic preference.
4. What is the role of AlCl₃ in halogenation of benzene?
AlCl₃ is a Lewis acid (electron pair acceptor). It accepts a lone pair from Cl₂: AlCl₃ + Cl₂ → AlCl₄⁻ + Cl⁺. The Cl⁺ is the actual electrophile that attacks benzene. Without AlCl₃, Cl₂ is not electrophilic enough to attack the π electron cloud of benzene (which is itself electron-rich). AlCl₃ "activates" Cl₂ by polarising it strongly. Other Lewis acid catalysts: FeBr₃ (for Br₂), FeCl₃ (for Cl₂) — both work the same way.
5. How many moles of Cl₂ are needed for complete chlorination of benzene?
For EAS (substitution): benzene has 6 H atoms → need 6 moles Cl₂ to replace all → C₆Cl₆ + 6HCl. For free radical addition: benzene has 3 double bonds (in Kekulé structure) → need 3 moles Cl₂ to add across all double bonds → C₆H₆Cl₆. Both products have 6 Cl atoms — just incorporated differently. In EAS: Cl replaces H (6 Cl atoms substitute 6 H atoms). In addition: Cl adds to double bonds (6 Cl atoms add to 6 ring carbons, H atoms remain).
6. What is hexachlorobenzene used for?
Hexachlorobenzene (C₆Cl₆) was used as: fungicide for seeds (treating wheat against bunt disease), wood preservative, intermediate in chemical synthesis. Now banned under the Stockholm Convention (2004) as a Persistent Organic Pollutant (POP). It is extremely persistent in soil and water, accumulates in fatty tissue, and is carcinogenic and toxic to liver and nervous system. Turkey outbreak (1955–1959): thousands of people developed porphyria cutanea tarda after eating hexachlorobenzene-treated seed wheat.
7. What are ortho/para directors? Give examples.
Ortho/para directors are substituents that direct incoming electrophile to ortho and para positions in EAS: (1) Activating o/p directors: −OH, −NH₂, −OCH₃, −NHR, −NHCOCH₃, −alkyl. They donate electrons to ring via resonance (especially to o and p positions). (2) Deactivating o/p directors: −F, −Cl, −Br, −I. They withdraw electrons by induction but donate by resonance (net deactivating, but o/p directing due to resonance). Meta directors (all deactivating): −NO₂, −CN, −COOH, −CHO, −SO₃H. These withdraw electrons via resonance, making o and p positions more deactivated than meta.
8. What is Friedel-Crafts alkylation and its limitation?
C₆H₆ + RCl →(AlCl₃) C₆H₅R. Limitations: (1) Polyalkylation — product (alkylbenzene) is more activated than benzene → reacts faster → gives di, tri, polyalkyl products. Difficult to stop at mono stage. (2) Rearrangement — carbocation (R⁺) can rearrange to more stable form before attacking benzene. (3) Does not work with deactivated arenes (e.g., nitrobenzene). (4) Does not work with −NH₂ group (amine coordinates to AlCl₃, deactivates it). Friedel-Crafts acylation gives ketones — no rearrangement possible since acylium ion (RCO⁺) is resonance-stabilised.
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