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In an optical bench experiment to find focal length of a convex lens, the object and image pins are at positions $u_{obs} = -30$ cm and $v_{obs} = +60$ cm. If the index correction for the object pin is $+0.2$ cm and for image pin is $-0.3$ cm, the corrected $u$ and $v$ are:

R
Solution written and verified by Roshan, science educator with 5 years of experience teaching NEET and JEE aspirants. Last reviewed September 2026.
Options
1
-29.8 cm and 59.7 cm
2
-30.2 cm and 60.3 cm
3
-30.2 cm and 59.7 cm
4
-29.8 cm and 60.3 cm
Correct Answer
-30.2 cm and 59.7 cm
Solution
1

Index correction for object = $-0.2$ → $u_{corr} = -30 + (-0.2) = -30.2$ cm

(Correction increases actual object distance by 0.2 cm)

2

Index correction for image = $-0.3$ → $v_{corr} = 60 + (-0.3) = 59.7$ cm

Answer: -30.2 cm and 59.7 cm

Corrected reading = Observed + index correction
u = -30+(-0.2) = -30.2 cm; v = 60+(-0.3) = 59.7 cm
Theory: Optics / Lab
1. Optical Instruments

Simple microscope: angular magnification $m = 1 + D/f$ (D=25 cm). Compound microscope: $m = m_o \times m_e = \frac{L}{f_o}(1+D/f_e)$ where $L$ = tube length. Telescope (astronomical): $m = f_o/f_e$; large $f_o$ (objective) needed for distant objects. Telescope for terrestrial use: erecting lens added (or Galilean type with diverging eyepiece) to give erect image.

2. Optical Aberrations

Spherical aberration: marginal rays focus at different point than paraxial rays (both chromatic and monochromatic). Corrected using: smaller aperture (reduce marginal rays), plano-convex lens properly oriented. Chromatic aberration: different wavelengths focus at different points (because $n$ depends on $\lambda$). Corrected using: achromatic doublet (crown glass + flint glass). Astigmatism, coma, distortion: other lens defects.

3. Human Eye and Vision Defects

Normal eye: far point = infinity (can see objects at any distance). Near point = 25 cm (least distance of distinct vision, D). Myopia (short-sightedness): far point < infinity → concave lens correction. Hypermetropia (long-sightedness): near point > 25 cm → convex lens correction. Presbyopia: loss of accommodation with age (near point increases) → bifocal or reading glasses. Astigmatism: cornea not spherical → cylindrical lens correction.

4. Wave Optics

Young\'s double slit experiment: $y_n = n\lambda D/d$ (bright fringe), $(2n+1)\lambda D/2d$ (dark fringe). Fringe width $\beta = \lambda D/d$. Conditions: fringe width increases with $\lambda$ (larger for red than violet), with $D$ (screen distance), decreases with $d$ (slit separation). Coherent sources required (same frequency, constant phase difference). Single slit diffraction: central maximum width $= 2\lambda/a$ (angular). Polarisation: Malus\'s law: $I = I_0\cos^2\theta$. Brewster\'s angle: $\tan\theta_B = n$ (for complete polarisation of reflected light).

Frequently Asked Questions
1. What is index correction? ⌄
Index correction accounts for the fact that the optical centre of a lens may not coincide with the index mark (pointer). If the actual position of lens differs from index mark, all distances measured need correction. Index correction = actual position - index position. Applied to all readings: corrected reading = observed reading + index correction.
2. What is lens formula? ⌄
$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$. Sign convention: distances measured from lens centre. Object on left: $u$ is negative. Image on right (real): $v$ is positive. $f$ for convex lens = positive.
3. How to find focal length in optical bench? ⌄
Setup: place convex lens between object pin O and image pin I. Move object/image pins until image of O coincides with pin I (no parallax). Measure $u$ = object distance, $v$ = image distance. Apply lens formula: $1/f = 1/v - 1/u$.
4. What is no-parallax condition? ⌄
Parallax: apparent shift of object relative to background when observer moves eye. No parallax: object and image coincide at same point. In optical bench: when image of object pin and real pin coincide, no parallax is observed on moving eye laterally. Indicates exact coincidence of image and pin.
5. What is meant by power of a lens? ⌄
$P = 1/f$ (f in metres), unit = Dioptre (D). Convex lens: $f > 0$, $P > 0$. Concave lens: $f < 0$, $P < 0$. Lenses in contact: $P_{total} = P_1 + P_2$. Spectacle lenses: +ve for hypermetropia (far-sightedness), -ve for myopia (near-sightedness). Normal human eye lens: ~20 D (plus cornea ~43 D → total ~63 D).
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